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Mars2501 [29]
3 years ago
9

If I use a plastic comb and run it "vigorously" through my hair, then hold it next to small torn pieces of tissue paper, what wo

uld happen?
Chemistry
2 answers:
wolverine [178]3 years ago
8 0
The paper would stick to the comb bc of static electricity
ioda3 years ago
3 0

Answer:

static or FIRE. I LOVE FIRE

Explanation:

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Chemistry help please! I just need to make sure the answers correct.... Thank you!
Veronika [31]
1. At constant tempaerature and pressure, 3 tablets produce 600cm^3 of gas
Thus calculating for 1 tablet that produces 600 / 3 = 200 cm^3
So now two tablets produce 200 x 2 = 400 cm^3
2. We have the equation PV = nRT, n being the number of moles
Pressure P = 1,000 kPa
Volume V = 3 L
R = 8.31 L kPa/mol-K
Temperature T = 298 K
n = PV / RT = (1000 x 3) / (8.31 x 298) = 3000 / 2476.38 = 1.21 moles
Number of moles = 1.21 moles.
8 0
3 years ago
Cansjhdhsbdhajajajhsbsbshs hahahah she jansbsbsns haha be safe
V125BC [204]

Answer:

wait what?

Explanation:

brainliest pls

4 0
3 years ago
"Compounds A and B react to give a single product, C. Write the rate law for each of the following cases and determine the units
olasank [31]

Answer:

Part a: <em>Units of k is </em>M^{-2}s^{-1}<em> where reaction is first order in A and second order in B</em>

Part b: <em>Units of k is </em>M^{-1}s^{-1}<em> where reaction is first order in A and second order overall.</em>

Part c: <em>Units of k is </em>M^{-1}s^{-1}<em> where reaction is independent of the concentration of A and second order overall.</em>

Part d: <em>Units of k is </em>M^{-3}s^{-1}<em> where reaction reaction is second order in both A and B.</em>

Explanation:

As the reaction is given as

A+B \rightarrow C

where as the rate is given as

r=k[A]^x[B]^y

where x is the order wrt A and y is the order wrt B.

Part a:

x=1 and y=2 now the reaction rate equation is given as

r=k[A]^1[B]^2

Now the units are given as

r=k[A]^1[B]^2\\M/s =k[M]^1[M]^2\\M/s =k[M]^{1+2}\\M/s =k[M]^{3}\\M^{1-3}/s =k\\M^{-2}s^{-1} =k

The units of k is M^{-2}s^{-1}

Part b:

x=1 and o=2

x+y=o

1+y=2

y=2-1

y=1

Now the reaction rate equation is given as

r=k[A]^1[B]^1

Now the units are given as

r=k[A]^1[B]^1\\M/s =k[M]^1[M]^1\\M/s =k[M]^{1+1}\\M/s =k[M]^{2}\\M^{1-2}/s =k\\M^{-1}s^{-1} =k

The units of k is M^{-1}s^{-1}

Part c:

x=0 and o=2

x+y=o

0+y=2

y=2

y=2

Now the reaction rate equation is given as

r=k[A]^0[B]^2

Now the units are given as

r=k[B]^2\\M/s =k[M]^2\\M/s =k[M]^{2}\\M^{1-2}/s =k\\M^{-1}s^{-1} =k

The units of k is M^{-1}s^{-1}

Part d:

x=2 and y=2

Now the reaction rate equation is given as

r=k[A]^2[B]^2

Now the units are given as

r=k[A]^2[B]^2\\M/s =k[M]^2[M]^2\\M/s =k[M]^{2+2}\\M/s =k[M]^{4}\\M^{1-4}/s =k\\M^{-3}s^{-1} =k

The units of k is M^{-3}s^{-1}

7 0
3 years ago
What is the molar mass of water (H2O)?
Sidana [21]

Answer:

The molar mass is: 18.02 g/mol.

Explanation:

  • Mass of two moles of Hydrogen atoms (H2) = 2x 1 g/mol = 2 g/mol.
  • Mass of one mole of water (H2O) = 2 g/mol + 16 g/mol = 18 g/mol.

1 mole of Hydrogen= 1.01, so if we have 2 moles of it here, that would be 2.02.

1 mole of Oxygen (that's all we have here)= 16.00

Once you add the two together (2.02+16.00), you will get 18.02.

I hope this made sense! Have a great day!

3 0
3 years ago
How many grams of KNO3, are needed to create 675.0 mL with a concentration of 1.71 M
valkas [14]

Answer:

Бардык белгилүү авиация мыйзамдарына ылайык, аары учуу мүмкүнчүлүгү жок. Канаттары өтө эле кичинекей, семиз денесин чече албайт. Албетте, аары баары бир учат. Себеби аарылар адам мүмкүн эмес деп эсептеген нерсеге маани бербейт.

Explanation:

Канаттары өтө эле кичинекей, семиз денесин чече албайт. Албетте, аары баары бир учат. Себеби аарылар адам мүмкүн эмес деп эсептеген нерсеге маани бербейт.

4 0
3 years ago
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