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Alinara [238K]
3 years ago
9

For my last question about the hemlock what would their height be at this time?

Mathematics
2 answers:
Klio2033 [76]3 years ago
6 0

Answer:

Western hemlocks have a height of 70 to 130 feet and a width of 20 to 30 feet.

Step-by-step explanation:

posledela3 years ago
3 0
I agree with the first one
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8/9d = 28 need help?
MariettaO [177]
Hey there.

8/9d = 28; multiply both sides by 9.

8d = 252; divide both sides by 8.

d = 31.5

I hope this helps!
7 0
4 years ago
43. Find the equation of a line perpendicular to the y-axis passing through the point (4, 7).
iVinArrow [24]

9514 1404 393

Answer:

  y = 7

Step-by-step explanation:

The y-axis is the vertical line x=0. A perpendicular line will be a horizontal line that will have an equation of the form ...

  y = constant

In order for that line to go through a point with y-coordinate 7, the line must be ...

  y = 7

6 0
3 years ago
Is 1/2 the opposite of 2
mylen [45]
<span> -2 is the opposite of 2
--------------------------------------
 -1/2 is the opposite of 1/2.</span>
5 0
3 years ago
Read 2 more answers
Solve the equation. Write the answer in terms of the natural logarithm.<br><br> 5e^{0.2x}=6[/tex]
Snezhnost [94]

Answer:

  • x = 5 ln 1.2

Step-by-step explanation:

  • 5e^{0.2x}=6
  • e^{0.2x}=6/5
  • e^{0.2x}=1.2
  • ln (e^{0.2x})= ln 1.2
  • 0.2x = ln 1.2
  • x = 5 ln 1.2
8 0
3 years ago
Read 2 more answers
Find an equation of the tangent to the curve at the given point by both eliminating the parameter and without eliminating the pa
Misha Larkins [42]

Answer:

y = 2x − 1

Step-by-step explanation:

By eliminating the parameter, first solve for t:

x = 4 + ln(t)

x − 4 = ln(t)

e^(x − 4) = t

Substitute:

y = t² + 6

y = (e^(x − 4))² + 6

y = e^(2x − 8) + 6

Taking derivative using chain rule:

dy/dx = e^(2x − 8) (2)

dy/dx = 2 e^(2x − 8)

Evaluating at x = 4:

dy/dx = 2 e^(8 − 8)

dy/dx = 2

Writing equation of line using point-slope form:

y − 7 = 2 (x − 4)

y = 2x − 1

Now, without eliminating the parameter, take derivative with respect to t:

x = 4 + ln(t)

dx/dt = 1/t

y = t² + 6

dy/dt = 2t

Finding dy/dx:

dy/dx = (dy/dt) / (dx/dt)

dy/dx = (2t) / (1/t)

dy/dx = 2t²

At the point (4, 7), t = 1.  Evaluating the derivative:

dy/dx = 2(1)²

dy/dx = 2

Writing equation of line using point-slope form:

y − 7 = 2 (x − 4)

y = 2x − 1

6 0
3 years ago
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