3,5, and 1 i think maybe i uhm yeah
Answer:
- Sn²⁺ ⇒ 1s² 2s² 2p⁶ 3s² 3p⁶ 4s² 3d¹⁰ 4p⁶ 5s² 4d¹⁰
- Ti⁺ ⇒ 1s² 2s² 2p⁶ 3s² 3p⁶ 4s² 3d¹⁰ 4p⁶ 5s² 4d¹⁰ 5p⁶ 4f¹⁴ 6s² 5d¹⁰
- As⁺³ ⇒ 1s² 2s² 2p⁶ 3s² 3p⁶ 4s²
Explanation:
The <em>electron configuration</em> indicates the way the electrons of an atom or ion are structured.<u> In the case of cations</u>, by knowing the electronic configuration of the atom (which is neutral), we can find out the cations' configuration by substracting <em>n</em> outermost electrons, where <em>n</em> is the charge of the cation.
Mg⁰ ⇒ [Ne] 3s² = 1s² 2s² 2p⁶ 3s². Thus
Mg⁺² ⇒ [Ne] = 1s² 2s² 2p⁶.
In a similar fashion, the answers are:
Sn²⁺ ⇒ 1s² 2s² 2p⁶ 3s² 3p⁶ 4s² 3d¹⁰ 4p⁶ 5s² 4d¹⁰
K⁺ ⇒ 1s² 2s² 2p⁶ 3s² 3p⁶
Al³⁺ ⇒ 1s² 2s² 2p⁶
Ti⁺ ⇒ 1s² 2s² 2p⁶ 3s² 3p⁶ 4s² 3d¹⁰ 4p⁶ 5s² 4d¹⁰ 5p⁶ 4f¹⁴ 6s² 5d¹⁰
As⁺³ ⇒ 1s² 2s² 2p⁶ 3s² 3p⁶ 4s²
Answer:
Chemical Change
Explanation:
A chemical change is when something is turned into a new substances.
In this example the wood is being turned into ash.
In the bookstore Avanti gave four books so it would be 1
Answer:
Bromine (Br) loses an electron, so it is the reducing agent.
Explanation:
A reducing agent also called a reducer, is known to be an electron donor. A reducing agent is oxidized, because it loses electrons in the redox reaction.
A oxidising agent also called a oxidant or oxidiser, is known to be an electron acceptor. A oxidising agent is reduced, because it gains electrons in the redox reaction.
Cl2(aq) + 2Br-(aq) --> 2Cl-(aq) + Br2(aq)
Half ionic equations,
Cl2(aq) + 2e- --> 2Cl-(aq)
2Br-(aq) --> Br2(aq) + 2e-
Reducing agent = Br-
Oxidizing agent = Cl2
