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Georgia [21]
3 years ago
14

The speed of a wave on a rope is 50cm/s an its wave length is 10cm. What is its frequency

Chemistry
1 answer:
pshichka [43]3 years ago
7 0

Answer:

Speed = frequency x wavelength 50 cm/s = Freq x 10cm

Explanation:

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What do all substances in the universe have in common?
Dmitry [639]

Answer:

All are made of matter

Explanation:

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3 years ago
Choose the compound responsible for the ir spectrum shown.
AVprozaik [17]

The right answer is the first molecule (3-methyl-butan-2-one).

There are many bands around 2900-3000 cm-1 proving the presence de C-H bound.

There an intense band in 1700 cm-1 proving the presence of C=O.

There's no band proving the presence of aromatic structure, C=C bond nor C-N bond.

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3 years ago
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You have a substance with a length of 2 cm, width of 3 cm, and a height of 4 cm. Its density is known to be .5 g/cm3. What is th
borishaifa [10]

Answer:

12 grams

Explanation:

D = m/V

0.5g/cm^3 = m/(2*3*4)

\frac{0.5g}{cm^3} = \frac{m}{24cm^3}

m = 12g

4 0
2 years ago
Think about how particles are arranged inside atoms. Please name and describe those three particles, and describe how the partic
vekshin1
Protons : positive charge , about same mass as neutrons , in the nucleus

neutrons : no charge , about the same mass as a proton , in the nucleus

electrons : negative charge , less mass than protons and neutrons , in orbitals outside of the nucleus
8 0
3 years ago
6.) 50.0 mol H2O<br> ? molecules
8_murik_8 [283]
<h3>Answer:</h3>

3.01 × 10²⁵ molecules H₂O

<h3>General Formulas and Concepts:</h3>

<u>Math</u>

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right

<u>Chemistry</u>

<u>Atomic Structure</u>

  • Using Dimensional Analysis
  • Avogadro's Number - 6.022 × 10²³ atoms, molecules, formula units, etc.
<h3>Explanation:</h3>

<u>Step 1: Define</u>

50.0 mol H₂O

<u>Step 2: Identify Conversions</u>

Avogadro's Number

<u>Step 3: Convert</u>

<u />\displaystyle 50.0 \ mol \ H_2O(\frac{6.022 \cdot 10^{23} \ molecules \ H_2O}{1 \ mol \ H_2O} ) = 3.011 × 10²⁵ molecules H₂O

<u>Step 4: Check</u>

<em>We are given 3 sig figs. Follow sig fig rules and round.</em>

3.011 × 10²⁵ molecules H₂O ≈ 3.01 × 10²⁵ molecules H₂O

5 0
3 years ago
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