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Ivahew [28]
3 years ago
12

How many moles of oxygen gas are required to form 55g of carbon monoxide gas

Chemistry
1 answer:
marta [7]3 years ago
6 0

Answer:

8.33 moles CO2 X. 25mol O2. 16mol CO2. = 13.0 moles

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Question 1 of 10
storchak [24]

Answer:

B. Convert mass percents to moles and then divide by the smallest mole value to get subscripts

Explanation:

The empirical formula is the smallest whole number ratio the elements in a compound can possess. According to this question, to derive the empirical formula of a compound from its percent composition of elements that make it up, the following steps are followed:

- First, since the elements are in percentage, one would assume the total mass of the compound is 100g and take each percentage as the mass of each element. For example, if a compound contains 16% oxygen, it means that 16g of oxygen is present.

- Next, we convert the mass of each element to moles by dividing the mass value by the molar mass of each element. For example, 16g of oxygen will be 16g/16g/mol = 1mol

- Next, we divide each mole value by the smallest mole value to get the subscript of each element that will be used in the empirical formula.

8 0
3 years ago
Read 2 more answers
If you were to burn a candle inside of a closed jar and the mass of the
sp2606 [1]

Answer:

50g

Explanation:

At the end of the burning process, the mass of the jar and smoke should be 50g after the candle burning is done.

In most systems, the law of conservation of matter finds expression. According to this law "matter is neither created nor destroyed but atoms are rearranged".

In this kind of system, no matter is allowed to escaped and the starting mass of the reactants compared to that of the product will be the same.

8 0
3 years ago
The image above shows a gas held in a chamber with a fixed volume. The gas begins with a temperature 333 K and a pressure of 4.0
lana66690 [7]

Answer:

636.86 K

Explanation:

From the question given above, the following data were obtained:

Initial temperature (T1) = 333 K

Initial pressure (P1) = 4 atm

Final pressure (P2) = 7.65 atm

Final temperature (T2) =?

NOTE: The volume is constant.

Since the volume is constant, we can obtain the new temperature the gas by using the following formula as illustrated below:

P1 /T1 = P2 /T2

4/333 = 7.65/T2

Cross multiply

4 × T2 = 333 × 7.65

4 × T2 = 2547.45

Divide both side by 4

T2 = 2547.45 / 4

T2 = 636.86 K

Therefore, the new temperature of the gas is 636.86 K

8 0
3 years ago
Read 2 more answers
The modern view of an electron orbital in an atom is best described as
Mrrafil [7]

invisable

you probably dont want to put that...

5 0
3 years ago
There are several aromatic compounds with the formula C8H9Cl. Draw those that have a trisubstituted ring where the methyl groups
Kryger [21]

Answer:

3-Chloro-1,2-dimethylbenzene

4-Chloro-1,2-dimethylbenzene

Explanation:

Such types of compounds in which conjugated planer ring system and delocalized pi electrons are present are called aromatic compounds such as Toluene, Benzene and some other. Generally, these compounds follow Huckle's rule. The trisubstituted ring means a compound in which three hydrogen atoms are replaced by three other groups. In the given compound  two hydrogen atoms are replaced by two methyl groups and one hydrogen atom is replaced by one Chlorine atom. From the given compound  3-Chloro-1,2-dimethylbenzene, and   4-Chloro-1,2-dimethylbenzene  can be drawn.

7 0
4 years ago
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