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Anon25 [30]
3 years ago
9

What happens when atoms bond?

Chemistry
1 answer:
Marrrta [24]3 years ago
4 0

Answer: Atoms form chemical bonds to make their outer electron shells more stable.

Explanation:

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Select the set of compounds that have the same empirical formula
Jobisdone [24]
Hello!

The set of compounds that have the same empirical formula is b) N₂O₄ and NO₂. 

The Empirical Formula is the most simple representation of the atom ratio in a chemical compound. Of the listed sets of compounds, the only in which the atom ratio is the same for both compounds is the pair N₂O₄ and NO₂ in which the atom ratio N:O is 1:2. The Empirical Formula for this pair is NO₂.

N₂O₄ has the same atom ratio as NO₂ but this formula has each atom multiplied by two. However, its Empirical Formula is the same. 

Have a nice day!
7 0
3 years ago
Chemical or physical change? and what made you think such?​
spayn [35]

Answer:

it's a chemical change and an electrolytic reaction

8 0
4 years ago
Read 2 more answers
What is always conserved in both physical and chemical changes, explain?
bonufazy [111]
All chemical reactions are chemical changes. The Law of Conservation of Matter states that matter cannot be created or destroyed. In a physical change, substances can change form, but the total mass remains the same. In a chemical change, the total mass of the reactants always equals the total mass of the products.
3 0
3 years ago
What is the correct unabbreviated electron configuration of the following?:
Rudik [331]

The correct  unabbreviated electron configuration  is as below


Vanadium - 1S2 2S2 2P6 3S2 3p6 3d3 4s2

Strontium -  1s2 2S2 2P6 3S2 3P6 3d10 4S2 4P6 4S2

Carbon =1S2 2S2 2P2


<u><em> Explanation</em></u>

vanadium  is in atomic number  23  in the periodic table  hence its electron configuration is 1s2 2s2 2p6 3s2 3p6 3d3 4s2

Strontium is in atomic number 38  in periodic table  hence  its electron configuration is 1s2 2s2 2p6 3s2 3p6 3d10  4s2 4p6 4s2

Carbon is in atomic number 6 in periodic  table  therefore its electron configuration is 1s2 2s2 2p2

5 0
4 years ago
An ionized helium atom has a mass of 6.6 × 10-27 kg and a speed of 5.3 × 105 m/s. It moves perpendicular to a 0.78-T magnetic fi
arsen [322]

Explanation:

In a magnetic field, the radius of the charged particle is as follows.

             r = \frac{mv}{qB}

where,   m = mass,      v = velocity

              q = charge,    B = magnetic field

Therefore, q will be calculated as follows.

         q = \frac{mv}{rB}

            = \frac{6.6 \times 10^{-27} \times 5.3 \times 10^{5}}{0.014 m \times 0.78 T}

            = \frac{34.98 \times 10^{-22}}{0.01092}

            = 3.2 \times 10^{-19} \times \frac{1.0 e}{1.6 \times 10^{-19}C}

            = +2e

Thus, we can conclude that the charge of the ionized atom is +2e.

5 0
3 years ago
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