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Kryger [21]
2 years ago
14

Which of the choices is an example of an element? O CO O Co O C2H2O2 O CO2

Chemistry
1 answer:
alukav5142 [94]2 years ago
3 0

Answer:

Co(cobalt) is the answer

Explanation:

Cobalt is a chemical element with the symbol Co and atomic number 27. Like nickel, cobalt is found in the Earth's crust only in chemically combined form, save for small deposits found in alloys of natural meteoric iron. The free element, produced by reductive smelting, is a hard, lustrous, silver-gray metal.

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Answer: Percent recovery is 47.34 %

Explanation:

Percent yield is defined as the ratio of experimental yiled to theoretical yield in terms of percentage.

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{\text{ percent yield}}=\frac{0.732}{1.546}\times 100=47.34\%

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Calculate the molar solubility of ag2so4 in each solution below. the ksp of silver sulfate is 1.5 × 10−5. (a) 0.36 m agno3: (b)
Lana71 [14]

Answer:

a) 1.157 x 10⁻⁴ M.

b) 0.0032 M.

Explanation:

  • Ag₂SO₄ is sparingly soluble salt in water which is dissociate according to:

<em>Ag₂SO₄ ⇄ 2Ag⁺ + SO₄²⁻.</em>

Ksp = [Ag⁺][SO₄²⁻] = (2s)²(s) = 1.5 x 10⁻⁵.

4s³ = 1.5 x 10⁻⁵.

s³ = 1.5 x 10⁻⁵/4 = 3.75 x 10⁻⁶.

∴ s = ∛(3.75 x 10⁻⁶) = 0.0155 M.

<em>a) 0.36 M AgNO₃:</em>

  • The dissociation of Ag₂SO₄: Ag₂SO₄ ⇄ 2Ag⁺ + SO₄²⁻, will be accompanied by the ionization of AgNO₃:

<em>AgNO₃ → Ag⁺ + NO₃⁻.</em>

  • So, the concentration of Ag⁺ will be that of AgNO₃  and Ag₂SO₄:

[Ag⁺] = (2s + 0.36)², s is neglected with respect to 0.36 M the concentration resulted from AgNO₃.

So, [Ag⁺] = (0.36)².

∴ Ksp = [Ag⁺][SO₄²⁻] = (0.36)²(s) = 1.5 x 10⁻⁵.

<em>∴ s </em>= 1.5 x 10⁻⁵/(0.36)² =<em> 1.157 x 10⁻⁴ M.</em>

<em>b) 0.36 M Na₂SO₄:</em>

  • The dissociation of Ag₂SO₄: Ag₂SO₄ ⇄ 2Ag⁺ + SO₄²⁻, will be accompanied by the ionization of Na₂SO₄:

Na₂SO₄ → 2Na⁺ + SO₄²⁻.

  • So, the concentration of SO₄²⁻ will be that of Na₂SO₄  and Ag₂SO₄:

[SO₄²⁻] = (s + 0.36), s is neglected with respect to 0.36 M the concentration resulted from Na₂SO₄.

<em>So, [SO₄²⁻] = (0.36).</em>

∴ Ksp = [Ag⁺][SO₄²⁻] = (2s)²(0.36) = 1.5 x 10⁻⁵.

∴ 4s² = 1.5 x 10⁻⁵/(0.36) = 4.166 x 10⁻⁵.

∴ s² = 4.166 x 10⁻⁵/4 = 1.042 x 10⁻⁵.

<em>∴ s</em> = √(1.042 x 10⁻⁵) = <em>0.0032 M.</em>

7 0
3 years ago
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