Velocity = 15 m/s
90/2 = 45 m
45/3 (seconds to reach) = 15 m
Show the two (neutral) organic starting materials that would be used to synthesize the following ketone by a hydroxide mediated crossed‑aldol reaction the product formed is alpha-beta unsaturated carbonyl compound.
<h3>What is the Aldol-condensation ?</h3>
The condensation response among distinctive molecules of an aldehyde or ketone in a protic solvent which includes water or alcohol constitutes the crossed aldol response. When condensation is among distinctive carbonyl compounds, it's far referred to as crossed aldol condensation.
Applying the retrosynthetic evaluation technique, the systems of the beginning substances are decided via way of means of the usage of the bottom catalyzed for the crossed aldol mechanism. The beginning substances are aldehyde and ketone compounds that react with every different to present the goal molecule.
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Answer:
The right answer is "16.67 mL".
Explanation:
Given:
Molarity of NaOH,


Volume of NaOH,


As we know, the equation,
⇒ 
On putting the values, we get
⇒ 
⇒ 
⇒ 
⇒
Answer:
Si ha mirado una tabla periódica, es posible que haya notado que la masa atómica de un elemento rara vez es un número par. Dupdo
Un Dalton, también conocido como unidad de masa atómica, es aproximadamente la masa de un solo protón o neutrón. Dupdo
Es decir, el deuterio tiene el doble de masa atómica que el protio y el tritio tiene tres veces la masa atómica del protio. Dupdo
El número bariónico, que es equivalente al número de masa atómica, debe permanecer constante para que se produzca una reacción.
Explanation:
According to Raoult's low:
We will use this formula: Vp(Solution) = mole fraction of solvent * Vp(solvent)
∴ mole fraction of solvent = Vp(Solu) / Vp (Solv)
when we have Vp(solu) = 25.7 torr & Vp(solv) = 31.8 torr
So by substitution:
∴ mole fraction of solvent = 25.7 / 31.8 =0.808
when we assume the moles of solute NaCl = X
and according to the mole fraction of solvent formula:
mole fraction of solvent = moles of solvent / (moles of solvent + moles of solute)
by substitute:
∴ 0.808 = 0.115 / (0.115 + X)
So X (the no.of moles of NaCl) = 0.027 m