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3 years ago

Ethylene glycol (antifreeze) has a density of 1.11 g/cm^3. What is the volume in liters of 3.46 kg of ethylene glycol?

Chemistry

2 answers:

xenn [34]3 years ago

7 0

3.11 i'm not sure about measurements maybe like 3.11kg/cm^3

liberstina [14]3 years ago

3 0

It is 3.12 you have to round

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When you need to produce a variety of diluted solutions of a solute, you can dilute a series of stock solutions. A stock solutio

8090 [49]

Answer:

Volume of stock solution needed = 6.0299 mL

Explanation:

<u> </u>Dilution consists of lowering the amount of solute per unit volume of solution. It is achieved by adding more diluent to the same amount of solute.

This is deduced when thinking that both the dissolution at the beginning and at the end will have the same amount of moles.

M1 = 6.01 M stock solution concentration

M2 = 0.3624 M diluted solution concentration

V2 =100 mL diluted solution volume

V1 = ? stock solution volume

M1 * V1 = M2 * V2

$V1=\frac{M2*V2}{M1} =\frac{0.3624M*100mL}{6.01M} =6.0299 mL$

4 0

3 years ago

A gas used to extinguish fires is composed of 75 % CO2 and 25 % N2. It is stored in a 5 m3 tank at 300 kPa and 25 °C. What is th

tatyana61 [14]

Answer : The partial pressure of the $CO_2$ in the tank in psia is, 32.6 psia.

Explanation :

As we are given 75 % $CO_2$ and 25 % $N_2$ in terms of volume.

First we have to calculate the moles of $CO_2$ and $N_2$ .

$\text{Moles of }CO_2=\frac{\text{Volume of }CO_2}{\text{Volume at STP}}=\frac{75}{22.4}=3.35mole$

$\text{Moles of }N_2=\frac{\text{Volume of }N_2}{\text{Volume at STP}}=\frac{25}{22.4}=1.12mole$

Now we have to calculate the mole fraction of $CO_2$ .

$\text{Mole fraction of }CO_2=\frac{\text{Moles of }CO_2}{\text{Moles of }CO_2+\text{Moles of }N_2}$

$\text{Mole fraction of }CO_2=\frac{3.35}{3.35+1.12}=0.75$

Now we have to calculate the partial pressure of the $CO_2$ gas.

$\text{Partial pressure of }CO_2=\text{Mole fraction of }CO_2\times \text{Total pressure of gas}$

$\text{Partial pressure of }CO_2=0.75mole\times 300Kpa=225Kpa=225Kpa\times \frac{0.145\text{ psia}}{1Kpa}=32.625\text{ psia}$

conversion used : (1 Kpa = 0.145 psia)

Therefore, the partial pressure of the $CO_2$ in the tank in psia is, 32.6 psia.

3 0

2 years ago

Which forms of drugs dissolve gradually to release the drug slowly? Check all that apply.

STALIN [3.7K]

<h3><u>Answer;</u></h3>

Bead
Pellet
Wafer

<h3><u>Explanation;</u></h3>

Bead is a drug fashioned into small, round objects that dissolve gradually to release the drug slowly
Pellet is a drug fashioned into small, bullet-shaped objects that dissolve gradually to release the drug slowly
Wafer is a drug fashioned into a thin disk that dissolves gradually to release the drug slowly

4 0

3 years ago

Your town is at sea level, and it is a comfortable room-

avanturin [10]

Answer:

68.6 m

Explanation:

Speed is defined as distance covered per unit time and expressed as

S=d/t

Where d is distance and t is speed.

Making d the subject of the above formula then

d=st

Substituting 343 m/s dor s and 0.200 s for s then

d=343*0.2=68.6 m

Therefore, the distance is 68.6 m

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3 years ago

Scientists can change society by defending their work in the face of controversy true or false

VMariaS [17]

they're not speaking to you and your family a very happy and prosperous new year and I will be there at first I thought it would be a good time to come by and see you soon

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3 years ago