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nikitadnepr [17]
3 years ago
14

Ethylene glycol (antifreeze) has a density of 1.11 g/cm^3. What is the volume in liters of 3.46 kg of ethylene glycol?

Chemistry
2 answers:
xenn [34]3 years ago
7 0
3.11 i'm not sure about measurements  maybe like 3.11kg/cm^3
liberstina [14]3 years ago
3 0
It is 3.12 you have to round

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If the ratio of the length of a rectangle to its width is 3 to 2, what is the
borishaifa [10]

Answer:

Length of a rectangle whose width is 4 inches is

<u>6 inches</u>

Explanation:

Ratio of length  to its width is 3 to 2

Let length  = L

Let Width  = B

L: B = 3 : 2 (given)

\frac{L}{B} =\frac{3}{2}

Width ,B = 4

Insert  B in above equation

\frac{L}{B} =\frac{3}{2}

\frac{L}{4} =\frac{3}{2}

cross multiply,

L = \frac{3}{2}\times4

L = 6 inches

Conversion(if required) ,

1 inch = 2.54 cm

6 inch = 2.54 (6)

L = 15.24 cm

8 0
3 years ago
Who was the first person known to have used the terms genus and species when classifying organisms?
velikii [3]

C Linnaeus was the first person known to have used the terms genus and species when classifying organisms.

4 0
3 years ago
During a combustion reaction, 9.00 grams of oxygen reacted with 3.00 grams of CH4.
Monica [59]

Answer:

0.74 grams of methane

Explanation:

The balanced equation of the combustion reaction of methane with oxygen is:

  • CH₄ + 2 O₂ → CO₂ + 2 H₂O

it is clear that 1 mol of CH₄ reacts with 2 mol of O₂.

firstly, we need to calculate the number of moles of both

for CH₄:

number of moles = mass / molar mass = (3.00 g) /  (16.00 g/mol) = 0.1875 mol.

for O₂:

number of moles = mass / molar mass = (9.00 g) /  (32.00 g/mol) = 0.2812 mol.

  • it is clear that O₂ is the limiting reactant and methane will leftover.

using cross multiplication

1 mol of  CH₄ needs → 2 mol of O₂

???  mol of  CH₄  needs → 0.2812 mol of O₂

∴ the number of mol of CH₄ needed = (0.2812 * 1) / 2 = 0.1406 mol

so 0.14 mol will react and the remaining CH₄

mol of CH₄ left over = 0.1875 -0.1406 = 0.0469 mol

now we convert moles into grams

mass of CH₄ left over = no. of mol of CH₄ left over *  molar mass

                                    = 0.0469 mol * 16 g/mol = 0.7504 g

So, the right choice is 0.74 grams of methane

3 0
3 years ago
What can be absorbed or produced as the result of a chemical reaction???
tia_tia [17]
Heat can be absorbed or produced
6 0
3 years ago
PLEASE HELP!! How could using either more or less of a chemical in a scientific experiment cause a change in results?
charle [14.2K]
The chemical could have more or less of a reaction to the other chemicals in the experiment
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