Answer:
12.68 m/s.
Explanation:
Equations of motion:
i. S = vi*t + 1/2 * a*(t^2)
ii. vf = vi + a*t
iii. vf^2 = vi^2 + 2a*S
Where, vf = final velocity
vi = initial velocity
S = distance travelled
a = acceleration due to gravity
t = time taken
Given:
vi = 0 m/s
S = 8.2 m
vf = ?
a = 9.81 m/s^2
Using iii. Equation of motion,
vf^2 = vi^2 + 2a*S
= 2 * 9.81 * 8.2
= 160.884
vf = sqrt (160.884)
= 12.68 m/s.
Stars are located at a distance which are measured in terms of light years. Light year is an Astronomical unit used to measure distance between distant Celestial bodies.
1 light year = 9460730472580<span>800 metres
But no star is located at a distance of 1 light year. Some stars are located at millions of light years and light travels ~ 3 x 10</span>⁸ m/s. Thus light takes time to reach our atmosphere.
Answer:
Explanation:
<u>Charge of an Electron</u>
Since Robert Millikan determined the charge of a single electron is
Every possible charged particle must have a charge that is an exact multiple of that elemental charge. For example, if a particle has 5 electrons in excess, thus its charge is
Let's test the possible charges listed in the question:
. We have just found it's a possible charge of a particle
. Since 3.2 is an exact multiple of 1.6, this is also a possible charge of the oil droplets
this is not a possible charge for an oil droplet since it's smaller than the charge of the electron, the smallest unit of charge
cannot be a possible charge for an oil droplet because they are not exact multiples of 1.6
Finally, the charge is four times the charge of the electron, so it is a possible value for the charge of an oil droplet
Summarizing, the following are the possible values for the charge of an oil droplet:
The concept related to this exercise to solve this problem is the ideal Gas law which establishes
P= Pressure
V= Volume
n = Number of moles
R= Gas ideal Constant
T= Temperature
Our values are given as,
From the ideal gas equation then we rearrange the equation to obtain the number of moles, then
By definition the molecular mass (n) is expressed in terms of the mass and molecular weight therefore
Therefore the mass of the helium in the blimp is 968.327Kg