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3 years ago

13

How is mechanical advantage determined in a pulley system?

1 answer:

ratelena [41]3 years ago

7 0

Answer:

<h3>To calculate the mechanical advantage of a pulley you simply have to count the number of rope sections that support whatever object you are lifting (not counting the rope that is attached to the effort). For example, in a one pulley system the MA is 1. ... The more compound the pulley is the easier the load is to lift.</h3>

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As a bullet shot vertically upward rises, the kinetic energy of the bullet

algol [13]

The kenitc energy of the bullet lowers as it keeps going up.

Because gravity is pushing the bullet down as the bullet goes up.

I'm pretty sure that the way to put this answer.

3 0

2 years ago

A car initially traveling 7 m/s speeds up uniformly at a rate of 3 m/s2 until it reaches a velocity of 22 m/s. How much time did

dezoksy [38]

Answer:

t = 5 s

Explanation:

Data:

Initial Velocity (Vo) = 7 m/s
Acceleration (a) = 3 m/s²
Final Velocity (Vf) = 22 m/s
Time (t) = ?

Use formula:

$\boxed{t=\frac{Vf - Vo}{a}}$

Replace:

$\boxed{t=\frac{22\frac{m}{s} -7\frac{m}{s}}{3\frac{m}{s^{2}}}}$

Solve the subtraction of the numerator:

$\boxed{t=\frac{15\frac{m}{s}}{3\frac{m}{s^{2}}}}$

It divides:

$\boxed{t=5\ s}$

How much time did it take the car to reach this final velocity?

It took a time of <u>5 seconds.</u>

8 0

2 years ago

A thin taut string is fixed at both ends and stretched along the horizontal x-axis with its left end at x = 0. It is vibrating i

Fofino [41]

Answer:

(a) Wavelength is 0.436 m

(b) Length is 0.872 m

(c) 11.518 m/s

Solution:

As per the question:

The eqn of the displacement is given by:

$y(x, t) = (1.22 cm)sin[14.4 m^{- 1}x]cos[(166\ rad/s)t]$ (1)

n = 4

Now,

We know the standard eqn is given by:

$y = AsinKxcos\omega t$ (2)

Now, on comparing eqn (1) and (2):

A = 1.22 cm

K = $14.4 m^{- 1}$

$\omega = 166\ rad/s$

where

A = Amplitude

K = Propagation constant

$\omega$ = angular velocity

Now, to calculate the string's wavelength,

(a) $K = \frac{2\pi}{\lambda}$

where

K = propagation vector

$\lambda = \frac{2\pi}{K}$

$\lambda = \frac{2\pi}{14.4} = 0.436\ m$

(b) The length of the string is given by:

$l = \frac{n\lambda}{2}$

$l = \frac{4\times 0.436}{2} = 0.872\ m$

(c) Now, we first find the frequency of the wave:

$\omega = 2\pi f$

$f = \frac{\omega}{2\pi}$

$f = \frac{2\pi}{166} = 26.42\ Hz$

Now,

Speed of the wave is given by:

$v = f\lambda$

$v = 26.419\times 0.436 = 11.518\ m/s$

4 0

3 years ago

How far does a car go in 30 seconds at a speed of 29 m/s? (The equation for<br> distance is d = st.)

Harrizon [31]

d = speed x time

distance = 29 x 30

distance = 870m

please mark as BRAINLIEST

8 0

2 years ago

What is the first step in wind formation?

sineoko [7]

Warm air expands and rises up while cold air condenses and sinks.

Hopefully I could help :)

5 0

3 years ago