Answer:
We need 41.2 L of propane
Explanation:
Step 1: Data given
volume of H2O = 165 L
Step 2: The balanced equation
C3H8(g) + 5O2(g) → 3CO2(g) + 4H2O(g)
Step 3: Calculate moles of H2O
1 mol = 22.4 L
165 L = 7.37 moles
Step 4: Calculate moles of propane
For 1 mol C3H8 we need 5 moles O2 to produce 3 moles CO2 and 4 moles H2O
For 7.37 moles H2O we need 7.37/4 = 1.84 moles propane
Step 5: Calculate volume of propane
1 mol = 22.4 L
1.84 moles = 41.2 L
We need 41.2 L of propane
Answer:
696 h
Explanation:
Let's consider the reduction of Cr³⁺.
Cr³⁺(aq) + 3e⁻ → Cr(s)
We can establish the following relations.
- The molar mass of Cr is 52.0 g/mol.
- 1 mol of Cr is deposited when 3 moles of e⁻ circulate.
- 1 mole of e⁻ has a charge of 96468 c (Faraday's constant).
- 1 A = 1 c/s
- 1 h = 3600 s
<em>How many hours will it take to plate 13.5 kg of chromium onto the cathode if the current passed through the cell is held constant at 30.0 A?</em>

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Answer:
No
Explanation:
loss of electron doesn't affect the element.
only change in proton number can, as we notice in nuclear chemistry.
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Answer:
4.867 L of ammonia
Explanation:
Using Haber's process to form ammonia using Nitrogen and hydrogen, the equation is :
N₂ + 3H₂ → 2NH₃
Here, 3 moles of hydrogen gas gives 2 moles of ammonia.
1 mole of any substance occupies 22.4L at STP
So, 3 x 22.4L of hydrogen gives 2 x 22.4 L of ammonia
Then 7.3 L of hydrogen will give:
=
=
= 4.867 L of ammonia