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4 years ago

Equation for progressive wave

Physics

1 answer:

koban [17]4 years ago

6 0

Answer:

y(x, t) = A Sin(ωt ± kx)

Explanation:

Waves can be classifies as either stationary (standing), or progressive (travelling). A progressive wave is one the is a traveling wave, transferring energy along its path. While a stationary wave seems not to be moving.

The general equation for a progressive wave is;

y(x, t) = A Sin(ωt ± kx)

Where: A is its amplitude, t is the time, k is the wave number.

When the wave travels in the positive x-axis direction, the equation changes to;

y(x, t) = A Sin(ωt - kx)

When it travels in the negative x- axis direction, the equation becomes;

y(x, t) = A Sin(ωt + kx)

NB: ω = 2 $\pi$ f and k = 2 $\pi$ /λ.

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An object is 10 cm from the mirror, its height is 1 cm and the focal length is 5 cm. What is the image height? (Indicate the obj

boyakko [2]

The image height is -10 cm (the image is upside down)

Explanation:

We can solve the problem by using the mirror equation:

$\frac{1}{f}=\frac{1}{p}+\frac{1}{q}$

where:

f = 5 cm is the focal length of the mirror

p = 10 cm is the distance of the object from the mirror

q is the distance of the image from the mirror

Solving for q, we find:

$\frac{1}{q}=\frac{1}{f}-\frac{1}{p}=\frac{1}{5}-\frac{1}{10}=\frac{1}{10}\\\rightarrow q= 10 cm$

So, the distance of the image from the mirror is 10 cm.

Now we can find the image height by using the magnification equation:

$\frac{y'}{y}=-\frac{q}{p}$

where

y' is the height of the image

y = 1 cm is the height of the object

and using

p = 10 cm

q = 10 cm

We find the size of the image:

$y' = -\frac{qy}{p}=-\frac{(10)(1)}{10}=-10 cm$

where the negative sign indicates that the image is upside down.

#LearnwithBrainly

8 0

3 years ago

--------------is an aquatic animal which emits electric discharge.

Varvara68 [4.7K]

Answer:

There are 5 of 'em.

It's so amazing.

1. The electric eel; It can generate about 370-650 volts of electric current from it's body.

2. The electric catfish!

About 350-450volts of electric current.

3. The electric Ray.

Say no more. It can generate about 37-220volts.

4. The electric stargazer (really stargazer, lol, and you live down the sea)

About 50volts

and

5. Skate.

Just 4volts.

You know more than to be careful when you go diving in the sea.

I love your question btw. I learnt also.

4 0

3 years ago

29. What is the average velocity of an object that moves

Murljashka [212]

Answer:

Average Velocity = - 1.22 cm/s = - 0.0122 m/s

Explanation:

The average velocity of an object is defined as the ratio of the total distance traveled by the object to the total time taken by the object to cover the distance. Therefore, the average velocity of an object can be found by the following formula:

Average Velocity = Total Distance Covered/Total Time Taken

Average Velocity = (Final Position - Initial Position)/Total Time Taken

Average Velocity = (3.7 cm - 6.5 cm)/(2.3 s)

Average Velocity = (- 2.8 cm)/(2.3 s)

<u>Average Velocity = - 1.22 cm/s = - 0.0122 m/s</u>

here, the negative sign indicates the direction of the velocity or the movement of the object is leftwards or towards the origin approaching from right.

3 0

3 years ago

What is the gravitational potential energy of the 6 kg cart as it sits the top of the incline?

ella [17]

There are some missing details in the question. Found them on internet:
- the mass of the cart is m=40 kg
- The height of the incline is h=300 m (see attached figure)

Solution:
the gravitational potential energy of an object is given by
$U=mgh$
where
m is the mass of the object
g is the gravitational acceleration
h is the height of the object above the reference point (usually taken as the ground)

By applying this formula, we find the potential energy of the cart at the top of the incline:
$U=mgh=(40 kg)(9.81 m/s^2)(300 m)=1.18 \cdot 10^5 J$