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Volgvan
3 years ago
14

Which ordered pair makes both inequalities true for y> -2x + 3 and y ≤ x - 2

Mathematics
1 answer:
lina2011 [118]3 years ago
6 0

Answer:

(2,0)

Step-by-step explanation:

Substitution, 0> -2(2) + 3 which equals, 0> -1 True

0= 2 - 2 True

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(2x + 7y = -24<br>18x+y=12 solve by substitution​
const2013 [10]

Answer:

x = .87, or when approximated to a fraction, 27/31

y = -3.67, or when approximated to a fraction, -1287/350

Step-by-step explanation:

Lets start by rewriting out our equations

2x + 7y = -24

18x + y = 12

Lets solve for a y value; the second equation is easiest, as the y value has no coefficient (the number that is multiplied times a variable). To do this, lets move the 18x to the other side. Now our two equations look like:

2x + 7y = -24

y = -18x + 12

Next, lets plus the second equation into the first equation in regards to y.

2x + 7(-18x + 12) = -24

Now, lets solve!

2x -126x + 84 = -24

Then, combine your terms!

-124x = -108

Divide by (-124)!

x = -108/-124

x = 27/31

Now that we know x, lets plug this back in to the first equation to find y!

2(27/31) + 7y = -24

1.74 + 7y = -24

7y = -25.74

y = -3.67, or when approximated to a fraction, -1287/350

4 0
3 years ago
Can someone please tell me what 597 ➗ 5 is
BigorU [14]

Answer:

119.4

Step-by-step explanation:

Big Brain Dude <:

5 0
3 years ago
Suppose a college student pays $500 for tuition fees. However, she also has to pay $250 for her textbooks (ouch!). What percent
Dominik [7]
750 dollars in total <=500+250=750
250/750=1/3 or 33.33333333% 
7 0
3 years ago
No links I can write equations to model real-world problems.
Llana [10]

Answer:

Hello I am here to help!! I personally think that it is A

Step-by-step explanation:

You can write equations like 2+2 for example.You can solve it for how many dollars this person has in their bank account. (This is just an example btw)

4 0
3 years ago
Read 2 more answers
Check out the photo for the question
Anestetic [448]

Answer:

50

Step-by-step explanation:

42/n³∑k²+12/n²∑k+30/n∑1

=42/n³[n(n+1)(2n+1)/6]+12/n²[n(n+1)/2]+30/n [n]

=7n(n+1)(2n+1)/n³+6n(n+1)/n²+30

=7(n+1)(2n+1)/n²+6(n+1)/n+30

=[7(2n²+3n+1)+6(n²+n)+30n²]/n²

=[14n²+21n+7+6n²+6n+30n²]/n²

=[50n²+27n+7]/n²

=[50+27/n+7/n²]

→50 as n→∞

because 1/n,1/n²→0 as n→∞

4 0
3 years ago
Read 2 more answers
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