Answer:
`1. charge Q, on the capacitor increases, while the current will decrease
2. τ = t = secs
Explanation:
1. consider RC of a circuit to be am external source
voltage across the circuit is given as
v =v₀(1 -
)
where v = voltage
v₀ = peak voltage
t = time taken
τ= time constant
as the charge across the capacitor increases, current decreases
the charge across the circuit is given as
Q= Q₀(1 -
)
charge Q is inversely proportional to the current I
hence the charge across the circuit increases
2. τ = RC
unit of time constant, τ,
= Ω × F
=
ˣ ![\frac{C}{V}](https://tex.z-dn.net/?f=%5Cfrac%7BC%7D%7BV%7D)
=![\frac{C}{A}](https://tex.z-dn.net/?f=%5Cfrac%7BC%7D%7BA%7D)
=![\frac{C}{C/t}](https://tex.z-dn.net/?f=%5Cfrac%7BC%7D%7BC%2Ft%7D)
τ = t = secs
Answer
A
Explanation:
Weight = Mass x Acceleration due to gravity
Weight = 1000 x 9.81
= 9810 or 9.81x10^ 3
Answer:
Gasoline is a liquid. Neon is a noble or inert gas, skin is solid
Explanation:
One of the most important reasons is that when mountains were built there were events such as tilting. Because of that most of the sedimentary rocks were no longer horizontal.We know that because of the law of original horizontality
Answer:
Normal force will be equal to 8.945 N
Explanation:
We have given mass of the cylinder m = 8.15 kg
Diameter d = 15 cm
So radius ![r=\frac{d}{2}=\frac{15}{2}=7.5cm = 0.075 m](https://tex.z-dn.net/?f=r%3D%5Cfrac%7Bd%7D%7B2%7D%3D%5Cfrac%7B15%7D%7B2%7D%3D7.5cm%20%3D%200.075%20m)
Initial angular velocity ![\omega _i=240rpm=\frac{2\times 3.14\times 240}{60}=25.12rad/sec](https://tex.z-dn.net/?f=%5Comega%20_i%3D240rpm%3D%5Cfrac%7B2%5Ctimes%203.14%5Ctimes%20240%7D%7B60%7D%3D25.12rad%2Fsec)
As the cylinder finally comes to rest so final angular velocity ![\omega _f=0rad/sec](https://tex.z-dn.net/?f=%5Comega%20_f%3D0rad%2Fsec)
Before coming to rest cylinder covers a distance of ![\Theta =5.20revolution=5.20\times 2\times 3.14=32.656rad](https://tex.z-dn.net/?f=%5CTheta%20%3D5.20revolution%3D5.20%5Ctimes%202%5Ctimes%203.14%3D32.656rad)
From third equation of motion ![\omega _f^2=\omega_i^2+2\alpha \Theta](https://tex.z-dn.net/?f=%5Comega%20_f%5E2%3D%5Comega_i%5E2%2B2%5Calpha%20%5CTheta)
![0^2=25.12^2-2\times \alpha \times32.656](https://tex.z-dn.net/?f=0%5E2%3D25.12%5E2-2%5Ctimes%20%5Calpha%20%5Ctimes32.656)
![\alpha =9.66rad/sec^2](https://tex.z-dn.net/?f=%5Calpha%20%3D9.66rad%2Fsec%5E2)
Coefficient of kinetic friction ![\mu _k=0.33](https://tex.z-dn.net/?f=%5Cmu%20_k%3D0.33)
Moment of inertia of the solid cylinder ![I=\frac{1}{2}mr^2](https://tex.z-dn.net/?f=I%3D%5Cfrac%7B1%7D%7B2%7Dmr%5E2)
We know that ![\tau =I\alpha](https://tex.z-dn.net/?f=%5Ctau%20%3DI%5Calpha)
![F\times r =(\frac{1}{2}mr^2)\times \alpha](https://tex.z-dn.net/?f=F%5Ctimes%20r%20%3D%28%5Cfrac%7B1%7D%7B2%7Dmr%5E2%29%5Ctimes%20%5Calpha)
![F =(\frac{1}{2}mr)\times \alpha](https://tex.z-dn.net/?f=F%20%20%3D%28%5Cfrac%7B1%7D%7B2%7Dmr%29%5Ctimes%20%5Calpha)
![F=\frac{1}{2}\times 8.15\times 0.075\times 9.66=2.952N](https://tex.z-dn.net/?f=F%3D%5Cfrac%7B1%7D%7B2%7D%5Ctimes%208.15%5Ctimes%200.075%5Ctimes%209.66%3D2.952N)
So normal force will be equal to ![N=\frac{F}{\mu _k}=\frac{2.952}{0.33}=8.945N](https://tex.z-dn.net/?f=N%3D%5Cfrac%7BF%7D%7B%5Cmu%20_k%7D%3D%5Cfrac%7B2.952%7D%7B0.33%7D%3D8.945N)