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belka [17]
3 years ago
12

You biked to the store in 10 minutes. The store was 3 km away. What was your average speed?

Physics
1 answer:
sineoko [7]3 years ago
4 0

Answer:

speed in km/min:

0.3km/min

speed in km/h:

18km/h

speed in m/s:

5m/s

Explanation:

the average speed is defined as:

s=\frac{d}{t}

where s is the speed, d is the distance traveled, and t is the time

according to the statement:

d=3km = 3,000m

and

t=10min=\frac{1}{6}h=600s (10 minutes are equal to a sixth of an hour which is 600 seconds)

Because the units in which the speed is required are not indicated, here are some options for the answer:

Depending on the units in which you need the speed, are the quantities you should use.

Speed in km / h (kilometers per hour):

s=\frac{3km}{\frac{1}{6}h }\\ \\s=18km/h

speed in m / s (meters per second):

s=\frac{3,000m}{600s}\\ s=5m/s

or the speed in km/min (kilometers per minute)

s=\frac{3km}{10min}\\ s=0.3km/min

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Use Net Force Equation.

Fnet = F1 + F2 + F3 + F4

In which the following main forces in play are:

F1 = Gravitational Force

F2 = Normal Force

F3 = Thrust Force

F4 = Air resistance

Since this is assumed to happen on a flat surface, the gravitational and normal forces cancel out. So we are left with:

Fnet = F(thrust) + F(air resistance)

Now we can use this equation to solve for the net force.

Fnet = 10N [right] + 7N [left]

Fnet = 10N [right] - 7N [right]

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7 0
3 years ago
A rifle with a weight of 25 N fires a 4.5-g bullet with a speed of 240 m/s. (a) Find the recoil speed of the rifle. m/s (b) If a
asambeis [7]

Answer:

The recoil speed of the man and rifle is v_{man}=0.016 ms^{-1}.

Explanation:

The expression for the force in terms of mg is as follows;

F=mg

Here, m is the mass and acceleration due to gravity.

Rearrange the expression for mass.

m=\frac{F}{g}

Calculate the combined mass of the man and rifle.

m_{man,rifle}=\frac{650+25}{g}

Put g=9.8 ms^{-2}.

m_{man,rifle}=\frac{650+25}{9.8}

m_{man,rifle}=68.88 kg

The expression for the conservation of momentum is as follows as;

m_{man}u_{man}+m_{bullet}u_{bullet}=m_{man}v_{man}+m_{rifle}v_{man,rifle}

Here, m_{man,rifle} is the mass of the man and rifle,  m_{rifle} is the mass of the rifle,u_{man},u{bullet}  are the initial velocities of the man and bullet and v_{man},v{man,rifle} are the final velocities of the man and rifle and rifle.

It is given in the problem that a rifle with a weight of 25 N fires a 4.5-g bullet with a speed of 240 m/s.

Convert mass of rifle from gram to kilogram.

m_{bullet}=4.5 g

m_{bullet}=.0045 kg

Put m_{bullet}=.0045 kg,m_{man,rifle}=68.88 kg , u_{man,rifle}=0, v_{bullet}= 240 ms^{-1} and u_{bullet}=0.

m_{man}(0)+m_{bullet}(0)=(68.88)v_{man,rifle}+(.0045)(240)

0=(68.88)v_{man,rifle}+(.0045)(240)

0=(68.88)v_{man,rifle}+1.08

(68.88)v_{man,rifle}=\frac{-1.08}{68.88}

v_{man,rifle}=-0.016 ms^{-1}  

Therefore, the recoil speed of the man and rifle is v_{man}=0.016 ms^{-1}.

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Answer:

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Answer:

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