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allsm [11]
3 years ago
14

Three 9W -3 V bulbs is to be lighted by a suppy of 12 Volt.For this,a wire is to be connected in series with it.Th resistance of

the wire should be:
A) 1
B) 2
C) 3
D) 4
Physics
2 answers:
Ivan3 years ago
7 0
9W 3V bulb need current flow
I = P/V = 9/3 = 3A

connected serially, voltage drop on the wire will be = Vsupply - 3(Vbulb) = 12 - 3(3) = 3V.

resistance of the wire ,with I=3 and V=3, = V/I = 3/3 = 1 Ohm.
Darina [25.2K]3 years ago
4 0
In order for a 3V bulb to dissipate 9W, the current through it must be 3A.
R = E/I = 3v/3A .  The resistance of such a bulb is 1 ohm.

There are two correct answers to the question, since the question itself
is ambiguous and may be understood in two different ways (at least) ...
series and parallel.

If the three bulbs are in series and the mystery wire will be placed
in series with them, then . . . . .

-- The current everywhere in the series circuit is 3 A .
-- The resistance across the supply is  R = E/I = 12v/3A  =  4 ohms.
-- 3 of the total 4 ohms is in the bulbs.
-- The additional wire must provide the additional 1 ohm .

If the three bulbs are in parallel and the mystery wire will be placed
in series with them, then . . . . .

-- The three bulbs in parallel form an effective resistance of 1/3 ohm.
-- The voltage across the parallel section of the circuit is 3v.
-- The additional wire must drop 9 volts across itself. 
-- The total current through the 3 branches of the parallel section,
    as well as through the additional piece of wire in series with it, is 9 A.
--  The resistance of the wire must be  R = E/I  =  9v/9A = 1 ohm.

Verrry interesting ! 
Whether the bulbs are in series or in parallel,
the same 1-ohm piece of wire does the job.
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A negative charge is moved from point A to point B along an equipotential surface. Which of the following statements must be tru
elena-s [515]

Answer:

C) No work is required to move the negative charge from point A to point B.

Explanation:

An equipotential surface is defined as a surface connecting all the points at the same potential.

Therefore, when a charge moves along an equipotential surface, it moves between points at same potential.

The work done when moving a charge is given by

W=q\Delta V

where

q is the charge

\Delta V is the potential difference between the initial and final point of motion of the charge

However, the charge in this problem moves along an equipotential surface: this means that the potential does not change, so

\Delta V=0

And so, the work done is also zero.

7 0
3 years ago
Why do skiers often wear sunglasses while they are skiing
yulyashka [42]
There is a lot of glare off of the ice, due to the sun and it also is always good to have eye protection in case you fall face first :P
4 0
3 years ago
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Which statements provides evidence that the earth revolves around the sun
Aloiza [94]

Answer:

Different star constellations are visible from Earth at different seasons of the year.

Explanation:

The reason the fact that we can see different constellations in the sky during different seasons on earth is the most compelling reason we travel around the sun is because if the sun travelled around the earth, certain constellations would only be visible in certain places. You’d have to travel to see certain ones.

However, you don’t have to do that because we travel around the sun, therefore travelling around other stars too.

4 0
3 years ago
What are the two principle advantages of telescopes over eyes?
Stells [14]

Answer:

i) Telescopes can be used to view far distant objects but the human eye can't view far distant objects.

ii) Telescopes uses two convex lenses producing a magnified image while the human eye only possesses one convex lens (image seen are smaller than that viewed under telescopes)

Explanation:

The telescopes can be used to view far distant objects due to their presence of two convex lenses. The two convex lenses are the objective lens (lens closer to object) and the eye piece lens (lens closer to eye). The object to be viewed forms an intermediate image first before the final image is seen using the eye piece lens.

The human eye only possess one convex lens and as such cannot view far ranged objects.

8 0
3 years ago
Approximate the Sun as a uniform sphere of radius 6.96 X 108 m, rotating about its central axis with a period of 25.4 days. Supp
In-s [12.5K]

Answer:

T = 184 seconds

Explanation:

First in order to solve this, we need to know which is the expression to calculate the period. This is an exercise of angular velocity, so:

T = 2π/w

Where w: angular speed (in rad/s)

So, let's calculate first the innitial angular speed:

w = 2π/T

Converting days to seconds:

25.4 days * 24 h/day * 3600 s/h = 2,194,560 s

Then the angular speed:

w = 2π / 2,194,560 = 2.863x10^-6 rad/s

Now, the innitial angular momentum is:

I = (2/5)Mr² replacing data:

I = 2/5* (6.96x10^8)² * M = 1.94x10^17m² * M

so the initial angular momentum would be:

L = Iω = 2.863x10^-6 * 1.94x10^17 M

L = 5.55x10^11 m²/s * M = final angular momentum

Now the  final I = 2/5Mr²

Final I = 2/5 * (6.37x10^6)² * M  = 1.62x10^13m² * M

Then 5.55x10^11m²/s * M = 1.62x10^13m² * M * ω → M cancels

ω = 3.42x10^-2 rad/s

Then the new period

T = 2π/ω = 2*3.14 / 3.42x10^-2

T = 184 seconds

8 0
3 years ago
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