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Andreas93 [3]
3 years ago
5

How do you know that forces are balanced when static friction acts on an object?

Physics
1 answer:
lyudmila [28]3 years ago
6 0
By looking at the acceleration of the object.
In fact, Netwon's second law states that the resultant of the forces acting on an object is equal to the product between the mass m of the object and its acceleration:
\sum F = ma

So, when static friction is acting on the object, if the object is still not moving we know that all the forces are balanced: in fact, since the object is stationary, its acceleration is zero, and so the resultant of the forces (left term in the formula) must be zero as well (i.e. the forces are balanced).
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Ne4ueva [31]

Answer:

see below

Explanation:

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3 0
3 years ago
The illustration represents one form of _________________, the process that enables all stars, including our sun, to continuousl
jonny [76]

We have no way to say what the illustration represents, mainly because
you haven't given us a way to see the illustration.

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8 0
3 years ago
Read 2 more answers
4) For the situation pictured below, F1 = 20.0 N east and F2 = 30.0 N west ,
maksim [4K]

Answer:

10.0 N West

Explanation:

Imagine East is positive and West is negative. Essentially now we have 2 forces pulling opposite each other on the same plane, so we can add them up.

F1=20N

F2=-30N

F1+F2=Net Force

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8 0
3 years ago
A long string is pulled so that the tension in it increases by a factor of four. If the change in length is negligible, by what
rusak2 [61]

To solve this problem we will apply the concepts related to wave velocity as a function of the tension and linear mass density. This is

v = \sqrt{\frac{T}{\mu}}

Here

v = Wave speed

T = Tension

\mu = Linear mass density

From this proportion we can realize that the speed of the wave is directly proportional to the square of the tension

v \propto \sqrt{T}

Therefore, if there is an increase in tension of 4, the velocity will increase the square root of that proportion

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3 0
3 years ago
The largest watermelon ever grown had a mass of 118 kg. Suppose this watermelon were exhibited on a platform 5.00 m above the gr
WINSTONCH [101]

Answer: height = 3.98m

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h = 4610/ 118 * 9.8

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h = 3.98m

6 0
3 years ago
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