<u>Answer:</u> The amount of hydrogen sulfide needed is 6.2 moles and amount of sulfur dioxide gas produced is 6.2 moles
<u>Explanation:</u>
We are given:
Moles of oxygen gas = 9.3 moles
The chemical equation for the reaction of oxygen gas and hydrogen sulfide follows:

<u>For hydrogen sulfide:</u>
By Stoichiometry of the reaction:
3 moles of oxygen gas reacts with 2 moles of hydrogen sulfide
So, 9.3 moles of oxygen gas will react with =
of hydrogen sulfide
<u>For sulfur dioxide:</u>
By Stoichiometry of the reaction:
3 moles of oxygen gas produces 2 moles of sulfur dioxide
So, 9.3 moles of oxygen gas will produce =
of sulfur dioxide
Hence, the amount of hydrogen sulfide needed is 6.2 moles and amount of sulfur dioxide gas produced is 6.2 moles
Answer:
The density of the swimmer is 0.0342 lbm/in3.
This value makes sense as the density of the body is very similar to the water.
Explanation:
If the swimmers is floating, the weight of the swimmer must be equal to the upward buoyant force.
We can express the weight force as the product of density and volume of the swimmer.
Then

It makes sense as the density of the body is very similar to the water.
8305 grams of HNO3 would be needed to prepare 5.5L of a solution. Details on how to calculate mass is found below.
<h3>How to calculate mass?</h3>
The mass of a substance in a solution can be calculated using the following formula:
Density = mass ÷ volume
According to this question, 5.5L of a HNO3 solution is given.
Density of HNO3 is 1.51 g/cm³
Volume of HNO3 = 5500mL
1.51 = mass/5500
mass = 8305g
Therefore, 8305 grams of HNO3 would be needed to prepare 5.5L of a solution.
Learn more about mass at: brainly.com/question/19694949