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Kruka [31]
2 years ago
7

a steam engine work on its vicinity 285 k heat is released with the help of 225 c energy absorbed to the system what is the effi

ciency of steam engine explain the use of the rest of the energy physic problem
Physics
2 answers:
zvonat [6]2 years ago
8 0

The efficiency of steam engine is  26.66 %.

<h3>What is Efficiency?</h3>

The efficiency is defined as the work done by the engine divided by the heat supplied.

Work done is the difference between the heat supplied and heat rejected.

So, efficiency η = (Qs -Qr) / Qs

Given is the heat supplied Qs = 225 Joules and heat rejected Qr =285 . then the work done is

W = 225 -225 = - 60 Joules

Efficiency η  = 60/225 x 100%

η = 26.66 %

Thus, the efficiency of the steam engine is  26.66 %.

Learn more about efficiency.

brainly.com/question/13828557

#SPJ2

Elan Coil [88]2 years ago
6 0
Efficiency= change in Energy/ time or useful work done/ time
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Rachel is in a car that was struck by lightning. is she safe?
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yes she is very safe inside

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Examine the spectra of the four unknown substances shown below. What can you conclude?
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Line spectra are obtained when individual elements are heated using a high-voltage electrical discharge. This heating causes excitation of the element and a subsequent emission of distinct lines of colored light are obtained. Each element has its own unique emission line spectrum; therefore, if any of the tested substances were the same, their spectra would match. However, this is not the case so none of the substances are the same.
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A person with mass mp = 74 kg stands on a spinning platform disk with a radius of R = 2.31 m and mass md = 183 kg. The disk is i
timurjin [86]

Answer:

1) 883 kgm2

2) 532 kgm2

3) 2.99 rad/s

4) 944 J

5) 6.87 m/s2

6) 1.8 rad/s

Explanation:

1)Suppose the spinning platform disk is solid with a uniform distributed mass. Then its moments of inertia is:

I_d = m_dR^2/2 = 183*2.31^2/2 = 488 kgm^2

If we treat the person as a point mass, then the total moment of inertia of the system about the center of the disk when the person stands on the rim of the disk:

I_{rim} = I_d + m_pR^2 = 488 + 74*2.31^2 = 883 kgm^2

2) Similarly, he total moment of inertia of the system about the center of the disk when the person stands at the final location 2/3 of the way toward the center of the disk (1/3 of the radius from the center):

I_{R/3} = I_d + m_p(R/3)^2 = 488 + 74*(2.31/3)^2 = 532 kgm^2

3) Since there's no external force, we can apply the law of momentum conservation to calculate the angular velocity at R/3 from the center:

I_{rim}\omega_{rim} = I_{R/3}\omega_{R/3}

\omega_{R/3} = \frac{I_{rim}\omega_{rim}}{I_{R/3}}

\omega_{R/3} = \frac{883*1.8}{532} = 2.99 rad/s

4)Kinetic energy before:

E_{rim} = I_{rim}\omega_{rim}^2/2 = 883*1.8^2/2 = 1430 J

Kinetic energy after:

E_{R/3} = I_{R/3}\omega_{R/3}^2/2 = 532*2.99^2/2 = 2374 J

So the change in kinetic energy is: 2374 - 1430 = 944 J

5) a_c = \omega_{R/3}^2(R/3) = 2.99^2*(2.31/3) = 6.87 m/s^2

6) If the person now walks back to the rim of the disk, then his final angular speed would be back to the original, which is 1.8 rad/s due to conservation of angular momentum.

3 0
3 years ago
Q1) An aeroplane covers a certain distance at a speed of 240 kmph in 5 hours.To cover the same distance in 1(2/3) hours, it must
Pepsi [2]

Answer:

D) 720 kmph

Explanation:

First, let's find what distance this aeroplane covered. Distance (d) is the product of speed and time - here, we have a speed of 240 kmph and a time of 5 hours, gives us

d=240\cdot5=1200 km

Using that same fact, we can set up a new equation to solve for speed (s) when we have a distance of 1200 km and a time of 1 2/3 hours. For the sake of cleanliness, I'm gonna rewrite 1 2/3 as the improper fraction 5/3:

1200=(5/3)s

Multiplying both sides of the equation by 3/5:

s=(3/5)(1200)=720 kmph

So our answer is D.

8 0
2 years ago
On January 22, 1943, the temperature in Spearfish, South Dakota, rose from −4°F to 45°F in just 2 minutes. What was the temperat
Nimfa-mama [501]
The answer is the first one
4 0
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