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kaheart [24]
3 years ago
13

Magnesium carbonate decomposes on heating to form magnesium oxide and carbon dioxide as shown.

Chemistry
1 answer:
lorasvet [3.4K]3 years ago
7 0
C. 21.0g

that’s the aweeee
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Which of the following are membranous sacs abundant in kidney and liver cells?
atroni [7]

Answer: it’s B!! :)

6 0
3 years ago
a heliox tank contains 32% helium and 68% oxygen. the total pressure in the tank is 395 kPa. What is the partial pressure of oxy
trapecia [35]

Answer:

Pp O2 = 82.944 KPa

Explanation:

heliox tank:

∴ %wt He = 32%

∴ %wt O2 = 68%

∴ Pt = 395 KPa

⇒ Pp O2 = ?

assuming a mix of ideal gases at the temperature and volumen of the mix:

∴ Pi = RTni/V

∴ Pt = RTnt/V

⇒ Pi/Pt = ni/nt = Xi

⇒ Pi = (Xi)*(Pt)

∴ Xi: molar fraction (ni/nt)

⇒ 0.68 = mass O2/mass mix

assuming mass mix = 100 g

⇒ mass O2 = 68 g

∴ molar mass O2 = 32 g/mol

⇒ moles O2 = (68 g)(mol/32 g) = 2.125 mol O2

⇒ mass He = 32 g

∴ molar mass He = 4.0026 g/mol

⇒ moles He = (32 g)(mol/4.0026 g) = 7.995 mol He

⇒ nt = nO2 + nHe = 2.125 mol + 7.995 mol = 10.12 moles

molar fraction O2:

⇒ X O2 = nO2/nt = (2.125 mol/10.12 mol) = 0.2099

⇒ Pp O2 = (X O2)(Pt)

⇒ Pp O2 = (0.2099)(395 KPa)

⇒ Pp O2 = 82.944 KPa

6 0
3 years ago
10. Identify the products in the combustion of methane.
Oksanka [162]

Answer:

a. CO2 and H20

Explanation:

Chemically, this combustion process consists of a reaction between methane and oxygen in the air. When this reaction takes place, the result is carbon dioxide (CO2), water (H2O), and a great deal of energy. The following reaction represents the combustion of methane:

CH4[g] + 2 O2[g] -> CO2[g] + 2 H2O[g] + energy

One molecule of methane, (the [g] referred to above means it is gaseous form), combined with two oxygen molecules, react to form a carbon dioxide molecule, and two water molecules usually given off as steam or water vapor during the reaction and energy.

8 0
2 years ago
Please help me with this question!<br> Am I right?
muminat
You are right!! Good job!!!
5 0
3 years ago
How many moles of the Htion in 395 mL of 1.325 M sulfuric acid (H2SO4).
Irina18 [472]

Answer:

1.05 mol

Explanation:

Step 1: Given data

  • Molarity of sulfuric acid (M): 1.325 M (1.325 mol/L)
  • Volume of solution (V): 395 mL (0.395 L)

Step 2: Calculate the moles of sulfuric acid (n)

We will use the following expression.

M = n/V

n = M × V

n = 1.325 mol/L × 0.395 L = 0.523 mol

Step 3: Calculate the moles of H⁺

H₂SO₄ dissociates completely according to the following equation.

H₂SO₄ ⇒ 2 H⁺ + SO₄²⁻

The molar ratio of H₂SO₄ to H⁺ is 1:2. The moles of H⁺ are 2/1 × 0.523 mol = 1.05 mol.

7 0
2 years ago
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