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yanalaym [24]
3 years ago
12

4. There are 1.9 moles of Oxygen gas at a pressure of 3.50 atm, and the temperature is 65°C. What is the

Chemistry
1 answer:
bonufazy [111]3 years ago
4 0

Answer:

15.06 L

Explanation:

Using the ideal gas law equation:

PV = nRT

Where;

P = pressure (atm)

V = volume (L)

n = number of moles (mol)

R = gas law constant (0.0821 Latm/molK)

T = temperature (K)

According to the information provided in this question,

P = 3.50 atm

n = 1.9 moles

V = ?

T = 65°C = 65 + 273 = 338K

Using PV = nRT

V = nRT/P

V = (1.9 × 0.0821 × 338) ÷ (3.5)

V = 52.725 ÷ 3.5

V = 15.06 L

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Answer:

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Explanation:

Step 1: Write the balanced neutralization equation

MgO + 2 HCl ⇒ MgCl₂ + H₂O

Step 2: Calculate the mass corresponding to 640.0 mg of MgO

The molar mass of MgO is 40.30 g/mol. The moles corresponding to 640.0 mg (0.6400 g) of MgO are:

0.6400 g × (1 mol/40.30 g) = 0.01588 mol

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The molar ratio of MgO to HCl is 1:2. The moles of HCl are 2/1 × 0.01588 mol = 0.03176 mol

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0.03176 mol × (1 L/0.1000 mol) = 0.3176 L = 317.6 mL

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