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KengaRu [80]
2 years ago
13

Which property of sodium is not typical of a metal

Chemistry
1 answer:
MakcuM [25]2 years ago
8 0

Answer:

It's a soft metal, reactive and with a low melting point, with a relative density of 0,97 at 20ºC (68ºF)

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based on the article what are some of the advantages that can be given by radio frequency and microwaves​
bonufazy [111]

Answer:

higher data rates are

Explanation:

transmitted

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more antenna gain is possible

6 0
3 years ago
Below are 5 sets of potential solutes for you to compare. Both members of each pair are very soluble in water. If you had equal
Gelneren [198K]

Answer:

Option D. AlCl₃, MgC₂

Explanation:

We need to dissociate all the salts, to determine the i. (Van't Hoff factor).

The salt who has the highest value, will be the better conductor of electricity

CsCl  → Cs⁺  +  Cl⁻   i = 2

CaCl → Ca²⁺ +  Cl⁻   i = 2

CaS → Ca²⁺ +  S⁻²    i = 2

Li₂S → 2Li⁺  +  S⁻²    i = 3

KBr →  K⁺  +  Br⁻       i = 2

AlCl₃ →  Al³⁺ + 3Cl⁻   i = 4

MgC₂  →  Mg²⁺  +  2C⁻   i = 3

KI  →  K⁺  +  I⁻     i = 2

K₂S  →  2K⁺  + S⁻²   i = 3

The biggest i, is in pair D.

6 0
3 years ago
Which of the following is true for the actual yield of a reaction?
ludmilkaskok [199]

Answer:

It is always less than the theoretical yield

Explanation:

For many chemical reactions, the actual yield is usually less than the theoretical yield. This is due to possible loss in the process or inefficiency of the chemical reaction.

4 0
3 years ago
Read 2 more answers
What is the power produced by a light bulb with a voltage of 120 volts and a current of 0.045 amps? PLEASE HELP I HAVE 5 MINUTES
Artyom0805 [142]
The answer is 5.4! I found it on a an online calculator! 
8 0
3 years ago
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a compound has a molar mass of 129 g/mol if its empirical formula is C2H5N then what is the molecular formula
Elena-2011 [213]

Given :

A compound has a molar mass of 129 g/mol .

Empirical formula of compound is C₂H₅N .

To Find :

The molecular formula of the compound.

Solution :

Empirical mass of compound :

M_e = ( 2 \times 12 ) + ( 5 \times 1 ) + (  1  \times 14 )\\\\M_e = 43\ gram/mol

Now, n-factor is :

n = \dfrac{M}{M_e}\\\\n = \dfrac{129}{43}\\\\n = 3

Multiplying each atom in the formula by 3 , we get :

Molecular Formula, C₆H₁₅N₃

3 0
2 years ago
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