I need help!!!!!!! please

What does the abyssopelagic gets its energy and nutrients from?

uysha [10]

Answer:

The abyssal zone or abyssopelagic zone is a layer of the pelagic zone of the ocean. "Abyss" ... This region also contains a much higher concentration of nutrient salts, like ... Many animals also move very slowly to conserve energy. Their reproduction rates are also very slow, to decrease competition and conserve energy.

Explanation:

Rather than relying on producers to form the base of the food pyramid, organisms living in the abyssal zone must feed on the dead organic detritus that falls from oceanic layers above. ... For example, many of these organisms convert hydrogen sulfide to sulfate to produce chemical energy.

8 0

3 years ago

How many moles of KNO3 are in 37.5 mL of .445 M KNO3?

Kitty [74]

Convert 50mL to liters by dividing it by 1000 to get your liters value which should be 0.05 L
Now your formula is .20 = x/0.05
Solve for x to get your mol value and you should get 0.01 mol

3 0

4 years ago

Read 2 more answers

Consider the following reaction: CO(g)+2H2(g)⇌CH3OH(g) Kp=2.26×104 at 25 ∘C. Calculate ΔGrxn for the reaction at 25 ∘C under eac

nlexa [21]

Answer : The value of $\Delta G_{rxn}$ is, $8.867kJ/mole$

Explanation :

The formula used for $\Delta G_{rxn}$ is:

$\Delta G_{rxn}=\Delta G^o+RT\ln Q$ ............(1)

where,

$\Delta G_{rxn}$ = Gibbs free energy for the reaction

$\Delta G_^o$ = standard Gibbs free energy

R = gas constant = 8.314 J/mole.K

T = temperature = $25^oC=273+25=298K$

Q = reaction quotient

First we have to calculate the $\Delta G_^o$ .

Formula used :

$\Delta G^o=-RT\times \ln K_p$

Now put all the given values in this formula, we get:

$\Delta G^o=-(8.314J/mole.K)\times (298K)\times \ln (2.26\times 10^{4})$

$\Delta G^o=-24839.406J/mole=-24.83\times 10^3J/mole=-24.83kJ/mole$

Now we have to calculate the value of 'Q'.

The given balanced chemical reaction is,

$CO(g)+2H_2(g)\rightarrow CH_3OH(g)$

The expression for reaction quotient will be :

$Q=\frac{(p_{CH_3OH})}{(p_{CO})\times (p_{H_2})^2}$

In this expression, only gaseous or aqueous states are includes and pure liquid or solid states are omitted.

Now put all the given values in this expression, we get

$Q=\frac{(1.4)}{(1.2\times 10^{-2})\times (1.2\times 10^{-2})^2}$

$Q=8.1\times 10^{5}$

Now we have to calculate the value of $\Delta G_{rxn}$ by using relation (1).

$\Delta G_{rxn}=\Delta G^o+RT\ln Q$

Now put all the given values in this formula, we get:

$\Delta G_{rxn}=-24.83kJ/mole+(8.314\times 10^{-3}kJ/mole.K)\times (298K)\ln (8.1\times 10^{5})$

$\Delta G_{rxn}=8.867\times 10^3J/mole=8.867kJ/mole$

Therefore, the value of $\Delta G_{rxn}$ is, $8.867kJ/mole$

6 0

3 years ago

Which subatomic particles have approximately the same mass?

igor_vitrenko [27]

Answer:

The 3rd one is correct

Explanation:

Protons and neutrons have approximately the same mass, about 1.67 × 10−24 grams, which scientists define as one atomic mass unit (amu) or one Dalton. Each electron has a negative charge (−1) equal to the positive charge of a proton (+1). Neutrons are uncharged particles found within the nucleus.

8 0

3 years ago

Read 2 more answers

Where does oxidation occur in an electrochemical cell?

crimeas [40]

(3); try using the phrase "AN OX ate the RED CAT"
(anode=oxidation, reduction=cathode)

4 0

3 years ago

Read 2 more answers