Question

A 155-L helium balloon is heated from 24.0 C to 38.0 C. What would be its new volume assuming the pressure remains constant?

Answer 1

Answer:

New volume is 162.3 L

Explanation:

We will use Charles law to solve this problem. It states that the volume of a fixed mass of gas is directly proportion to its kelvin temperature, provided pressure is kept constant. Its mathematically represented below.

$\frac{V_{1} }{T_{1} } =\frac{V_{2} }{T_{2} }$

from the question;

V1=155L  

T1=24°C =24+273 =297K  

T2=38°C=38+273 = 311K

V2=?

$V_{2}= \frac{V_{1}T_{2} }{T_{1} }$

$V_{2}=\frac{155*311}{297}$

V2=162.3 L