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Misha Larkins [42]

3 years ago

6

A sled with no initial velocity accelerates at a rate of 3.2 m/s2 down a hill. How long does it take the sled to go 15 m to the

bottom? *

1 answer:

grin007 [14]3 years ago

3 0

S = ut + 1/2 at^2
a = 3.2 m/s^2
s = 15m
Find t
15 = 1/2(3.2)t^2
15 = 3.2t^2/2
30 = 3.2t^2
30/ 3.2 = 9.38
Square root of 9.38 = 3.06
It takes 3.06 seconds

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The equation for the variable $\rho$ is

$\rho =\frac{2\gamma \Phi+\Psi}{rg}$

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This means that:

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The term $2\gamma \Phi$ must have the same units of $\Psi$ in order to be added to it. Therefore,

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Therefore

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