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Dafna11 [192]
3 years ago
5

The photo shows a toy spring. What kind of energy does the toy have because of its shape?

Physics
2 answers:
Karo-lina-s [1.5K]3 years ago
8 0

Answer:

elastic

Explanation:

if you stretch it it will go back to its shape, and also it is the only one that makes sense.

ivanzaharov [21]3 years ago
8 0

Answer:

Elastic

Explanation:

I got it right

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3. What exerts a greater force on the table of 2 kg book lying flat or a 2 kg book on its
Darina [25.2K]

Answer:

A book on its side exerts a greater force.

Explanation:

Pressure = Force / Area

Assuming that 1kg = 10N

2kg = 20N

Area of book lying flat = 0.3m × 0.2m

                                     = 0.6m²

Pressure of book lying flat = 20N / 0.6m²

                                            = 30Pa (1 s.f.)

Area of book on its side = 0.2m × 0.05m

                                        = 0.01m²

Pressure of book on its side = 20N / 0.01m²

                                               = 2000Pa (1 s.f.)

Since 2000Pa (1 s.f.) > 30Pa (1 s.f.), a book on its side applies greater pressure than lying flat.

5 0
2 years ago
The electric field in a region of space increases from 0 0 to 3450 N/C 3450 N/C in 4.40 s. 4.40 s. What is the magnitude of the
slavikrds [6]

Answer: B = 1380T

Explanation: please find the attached file for the solution

7 0
3 years ago
A 14.8-g piece of Styrofoam carries a net charge of -0.742 µC and is suspended in equilibrium above the center of a large, horiz
MAXImum [283]
Base on your question where a 14.8g of piece of Styrofoam carries a net charge of -0.742C and is suspended in equilibrium above the center of a large, horizontal sheet of plastic so the ask of the problem is to calculate  the charge per unit area on the plastic sheet. The answer would be 21.96
3 0
3 years ago
A virtual image is formed 17.0 cm from a concave mirror having a radius of curvature of 39.0 cm. (a) Find the position of the ob
Wittaler [7]

Explanation:

Image distance, v = -17 cm (-ve for virtual image)

Radius of curvature of concave mirror, R = 39 cm

Focal length, f = -19.5 cm (-ve for a concave mirror)

(a) Using mirror's formula as :

\dfrac{1}{v}+\dfrac{1}{u}=\dfrac{1}{f}

\dfrac{1}{u}=\dfrac{1}{f}-\dfrac{1}{v}

\dfrac{1}{u}=\dfrac{1}{-19.5}-\dfrac{1}{(-17)}  

u = 132.6 cm    

So, the object is placed 132.6 cm in front of the mirror.

(b) Magnification of the  mirror, m=\dfrac{-v}{u}

m=\dfrac{-17}{132.6}

m = -0.128

Hence, this is the required solution.

7 0
3 years ago
2. Write five honest ways of earning money.?​
dimaraw [331]

Answer:

Get Hired

Start a business

rent out your house

Sell online

Take surveys

Explanation:

8 0
2 years ago
Read 2 more answers
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