Answer:
(a) FN = m (g - 
)
(b) vmin = 17.146 m/s
Explanation:
The radius of the arc is
r = 30m
The normal force acting on the car form the highest point is
FN = m (g - )
If the normal force become 0 we have
m (g - ) = 0
or
g - = 0
This way, when FN = 0, then v = vmin, so
g - 
= 0
vmin = ![\sqrt[.]{g*r}](https://tex.z-dn.net/?f=%5Csqrt%5B.%5D%7Bg%2Ar%7D)
= ![\sqrt[.]{9.8 m/s^{2} * 30m } = 17.146 m/s](https://tex.z-dn.net/?f=%5Csqrt%5B.%5D%7B9.8%20m%2Fs%5E%7B2%7D%20%2A%2030m%20%7D%20%3D%2017.146%20m%2Fs)
Answer:
3947.6 N
Explanation:
Centripetal Force: This is the force that tend to moves a body towards the center of a circle during circular motion.
The formula for centripetal force is
F = mω²r ........................ Equation 1
Where F = Centripetal force, ω = angular velocity, r = radius.
Where π = 3.1415
Given: m = 4 kg, ω = 0.5 rev/s = (0.5×2π) rad/s = 3.1415 rad/s, r = 100 m.
Substitute into equation 1
F = 4(3.1415)²(100)
F = 3947.6 N
Hence the centripetal force on the turbine blade = 3947.6 N
Answer:
(a) 0.204 Weber
(b) 0.22 Volt
Explanation:
N = 100, radius, r = 10 cm = 0.1 m, B = 0.0650 T, angle is 90 degree with the plane of coil, so theta = 0 degree with the normal of coil.
(a) Magnetic flux, Ф = N x B x A
Ф = 100 x 0.0650 x 3.14 x 0.1 0.1
Ф = 0.204 Weber
(b) B1 = 0.0650 T, B2 = 0.1 T, dt = 0.5 s
dB / dt = (B2 - B1) / dt = (0.1 - 0.0650) / 0.5 = 0.07 T / s
induced emf, e = N dФ/dt
e = N x A x dB/dt
e = 100 x 3.14 x 0.1 x 0.1 x 0.07 = 0.22 V
Answer:
(b) In ideal condition we neglect mass of spring but in real springs mass of spring adds another factor to its time period.
since we are adding a factor of mass to the system, and frequency being inversely proportional to squared root of mass, we can come to a general conclusion that it effectively reduces the natural frequency .
Explanation:
kindly check the attachment for explanation.
Answer:
diverging light rays of the bulb are collected by the reflector.
Explanation:
