Answer:
Complete question:
c.If the current in the second coil increases at a rate of 0.365 A/s , what is the magnitude of the induced emf in the first coil?
a.
b.flux through each turn = Ф =
c.magnitude of the induced emf in the first coil = e=
Explanation:
a. rate of current changing = [/tex]
Induced emf in the coil =e=
For mutual inductance in which change in flux in one coil induces emf in the second coil given by the farmula based on farady law
b.
Flux through each turn=?
Current in the first coil =1.25 A
Number of turns = 20
using MI = NФ
flux through each turn = Ф =
flux through each turn = Ф =
c.
second coil increase at a rate = 0.365 A/s
magnitude of the induced emf in the first coil =?
using
magnitude of the induced emf in the first coil = e=