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serious [3.7K]
3 years ago
14

What is the distance between two spheres, each with a charge of 2.5 x 10-6 c, when the force between them is 0.50 n?

Physics
1 answer:
lianna [129]3 years ago
7 0
In this case, Coulomb's Law applies:

F = 1/(4πε₀) · (Q₁Q₂/r²)

You can solve it for r:

r = √[1/(4πε₀) · (Q₁Q₂/F<span>)]

Plugging in numbers:

r = </span>√[1/(4π·8.85×10⁻¹²) · (2.5×10⁻⁶)²/0.50] 
  = 0.335m

The correct answer is: the two charges are 0.335m apart.
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Four squares are in a 2×2 grid.
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18) A charm quark has a charge of approximately
Allushta [10]

Based on scientific records, a charm quark has a charge that's approximately equal to: 2) 1.07 × 10⁻¹⁹ C.

<h3>What is a charge?</h3>

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Also, charge is typically measured in Coulombs and a charm quark (elementary particle) has a charge that's approximately equal to 1.07 × 10⁻¹⁹ Coulomb.

Read more on charges here: brainly.com/question/4313738

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3 0
2 years ago
Collaborative learning focuses on the learning of an individual. True or False
Jobisdone [24]

Answer:

False

Explanation:

The collaborative learning is not a type of learning that focuses on individual learning. This type of learning focuses on joint learning between two or more individuals that act as a team. The collaborative learning is a method that encourages the two or more individuals to work together, to capitalize on each other's skills and resources for the benefit of the whole, for the team. This type of learning has its own supporters and critics, as some consider it as excellent way to develop the team work and closer bonds between the people, while others argue that it is destroying the potential of the individual.

4 0
4 years ago
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A pendulum is made up of a small sphere of mass 0.500 kg attached to a string of length 0.950 m. The sphere is swinging back and
Semenov [28]

Answer:

W = 0.842 J

Explanation:

To solve this exercise we can use the relationship between work and kinetic energy

         W = ΔK

In this case the kinetic energy at point A is zero since the system is stopped

         W = K_f                (1)

now let's use conservation of energy

starting point. Highest point A

          Em₀ = U = m g h

Final point. Lowest point B

         Em_f = K = ½ m v²

energy is conserved

         Em₀ = Em_f

         mg h = K

to find the height let's use trigonometry

at point A

            cos 35 = x / L

            x = L cos 35

so at the height is

            h = L - L cos 35

            h = L (1-cos 35)

we substitute

           K = m g L (1 -cos 35)

we substitute in equation 1

           W = m g L (1 -cos 35)

let's calculate

           W = 0.500 9.8 0.950 (1 - cos 35)

           W = 0.842 J

7 0
3 years ago
A particle moving along the x-axis has its position described by the function x=(3.00t3−1.00t 2.00)m where t is in s. at t = 4.0
prohojiy [21]
X =(3.00x4.00 x3-1.00t x 2.00) x m

x= (12.00x3- 1.00 x2.00) x m
x= 36.00 -1.00 x 2.00) x m
x = (36.00 -2.00) x m
x =( 34.00) x m
x =34.00   times m
7 0
3 years ago
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