Answer:
In order to evaluate the given expression 17(144) using the distributive property, Julia would rewrite the expression in friendlier numbers that is:
(10+7)(100+40+4)
Step-by-step explanation:
We are given an expression 17(144) that we have to evaluate let us say without using the calculator.
Sometimes, it is easier to solve a complex problem in multiple steps as the problem gets distributed and the difficulty level lowers for multiple smaller sets.
Julia would rewrite the expression as:
(10+7)(100+40+4)
Then solve it using distribution method as follows:
10(100+40+4)+7(100+40+4)
1000+400+40+700+280+28
= 2448
Important: to denote exponentiation use " ^ ":
<span>(x + y)1 = ___ x + ___ y NO
</span><span>(x + y)^1 = ___ x + ___ y YES
(x+y)^1 = 1x + 1y
(x+y)^2 = 1x + 2xy + y^2
(x+y)^3 = 1x^3 + 3x^2*y + 3x*y^2 + y^3
and so on. Look up "Pascal's Triangle" if you want more info on this pattern.
*******************
</span><span>(x + y)4 = ___ x4 + ___ x3y + ___ x2y2 + ___ xy3 + ___ y4 NO
</span>
<span>(x + y)^4 = ___ x^4 + ___ x^3y + ___ x^2y^2 + ___ xy^3 + ___ y^4 YES
(x+y)^4 = 1x^4 + 4x^3*y + 6x^2*y^2 + 4x*y^3 + y^4</span>
-6x + 1 > -23 <=>
-6x > -24 <=>
x < 4
Answer:
13
Step-by-step explanation:
12^2 + 5^2 = c^2
144 + 25 = c^2
169 = c^2
13 = c
Answer:
10+10= 20/10= 2-0= 2+1000000000= 1000000002
Step-by-step explanation:
