The answer is 0.025J.
W=1/2*k*x^2
W=1/2*20*0.050^2
W=0.025J
Explanation:
A centripetal force (from Latin centrum, "center" and petere, "to seek") is a force that makes a body follow a curved path. (not sure but hope this helps )
Answer:
The center of mass of the Earth–Moon system is 4.613 × 10⁶ m from center of the Earth.
Explanation:
Let the reference point be the center of the Earth
Where;
Xcm is the distance from center of the Earth =?
Me is the mass of the Earth = 6 × 10²⁴ kg
Xe is the center mass of the Earth = 0
Mm is the mass of the moon = 7 × 10²² kg
Xm is the center mass of the moon = 4 × 10⁸ m
Therefore, the center of mass of the Earth–Moon system is 4.613 × 10⁶ m from center of the Earth.
2.0 meters The skateboarder has 2 forces acting upon him to slow him down. The forces are friction, and climbing against the gravitational acceleration. So let's calculate the magnitude of these forces to see how fast he's decelerated. The coefficient of kinetic friction is a multiplier to use against the normal force of the object. We can calculate the normal force by multiplying the mass of the object by the local gravitational acceleration and the cosine of the angle. So Df = 60 kg * 9.8 m/s^2 * cos(20°) * 0.30 Df = 60 kg * 9.8 m/s^2 * 0.939692621 * 0.30 Df = 60 kg * 9.8 m/s^2 * 0.939692621 * 0.30 Df = 165.7617783 kg*m/s^2 Df = 165.7617783 N
The second amount of force is that caused by gravitational acceleration while climbing. That is determine by the amount of height gained for every meter along the slope. We can calculate that using the sine of the angle. So
Dg = 60 kg * 9.8 m/s^2 * sin(20°)
Dg = 60 kg * 9.8 m/s^2 * 0.342020143
Dg = 201.1078443 kg*m/s^2
Dg = 201.1078443 N
So the amount of force decelerating the skateboarder is:
F = Df + Dg
F = 165.7617783 N + 201.1078443 N
F = 366.8696226 N
Now let's determine how much kinetic energy needs to be dissipated. The equation is
E = 0.5 MV^2
So we'll substitute the known values and calculate
E = 0.5 MV^2
E = 0.5* 60 kg * (5 m/s)^2
E = 0.5* 60 kg * 25 m^2/s^2
E = 750 kg*m^2/s^2
E = 750 J
Now let's divide the energy by the force.
750 kg*m^2/s^2 / 366.8696226 kg*m/s^2 = 2.04432298 m
Rounding to 2 significant figures gives a distance of 2.0 meters.
The Bhutan Forest Act of 1969, affect the lives of shifting cultivators because the act placed the status of Tsheri land on the same footing with wetland and rain-fed land.
<h3>What is shifting cultivators?</h3>
A field that had been developed whenever was left neglected for quite a long time, Shifting cultivators were tracked down in the sloping and forested lots of North-east and Central India. The existences of these ancestral individuals relied upon free development inside backwoods and on having the option to involve the land and woods for developing their harvests.
The Forest Act of 1969 has restricted new clearances for moving development however has not deterred the act of it where such development doesn't jeopardize the wellbeing of the roadway and public property. The Land Act of 1979 has put the situation with
Tsheri land on a similar footing with wetland and rain fed land.
Thus, Bhutan Forest Act of 1969, affect the lives of shifting cultivators.
Learn more about shifting cultivators
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