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3 years ago

Find the value of 10x+3 if 10x=1,5

Mathematics

1 answer:

pishuonlain [190]3 years ago

5 0

Answer:

If x=1 then 13, if x=5 then 53

Step-by-step explanation:

hope this helps

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Which statement is true about the graphs of the two lines y = –6 and x = 1/6 ?

ivanzaharov [21]

The lines are perpendicular to each other because the graph of y = –6 is a horizontal line with a slope that is undefined, and the graph of x = 1/6 is a vertical line with a slope of 0.
The lines are perpendicular to each other because the graph of y = –6 is a vertical line with a slope that is undefined, and the graph of x =1/6 is a horizontal line with a slope of 0.
The lines are perpendicular to each other because the graph of y = –6 is a vertical line with a slope of 0, and the graph of x =1/6 is a horizontal line with a slope that is undefined.
 The lines are perpendicular to each other because the graph of y = –6 is a horizontal line with a slope of 0, and the graph of x =1/6 is a vertical line with a slope that is undefined.

4 0

3 years ago

∆ABC is a right angled at B and D is a point on BC if AD = 18cm BD = 9cm and CD =4cm Find AC

Gemiola [76]

In triangle, ABD,

AD²= AB²+BD²

AB² = AD²-BD²

AB² = 18²-9² = 324-81 = 243

AB = √243

In triangle, ABC,

AC² = AB²+BC²

AC² = (√243)²+(13)²

AC² = 243+169

AC = √412

AC = 20.29

3 0

3 years ago

PLSSS HELP MEE PLSSSS

Elza [17]

C- 5 less than 6 times some number.
5 - 6t

6 0

2 years ago

Read 2 more answers

What is the slope of the line 3 + 4x = 2y - 9

SSSSS [86.1K]

Hello!

Ok so ideally we would like to see this in y=mx+b form. But it will take some algebreic skills to ninja our way through this.

I'll show my steps so you can follow,

3+4x = 2y - 9 (original equation)

Next we just add 9 to both sides,

12 + 4x = 2y, now we can divide both sides by 2,

y=2x+6 as our final equation. This is in y=mx+b form, thus the slope of our line is 2 because the 2 is sitting in the m space of the equation. If you still dont understand linear stuff, I'd google slope-intercept form

Hope this helped!

7 0

3 years ago

Let f(x) = [infinity] xn n2 n = 1. find the intervals of convergence for f. (enter your answers using interval notation. ) find

inna [77]

Best guess for the function is

$\displaystyle f(x) = \sum_{n=1}^\infty \frac{x^n}{n^2}$

By the ratio test, the series converges for

$\displaystyle \lim_{n\to\infty} \left|\frac{x^{n+1}}{(n+1)^2} \cdot \frac{n^2}{x^n}\right| = |x| \lim_{n\to\infty} \frac{n^2}{(n+1)^2} = |x| < 1$

When $x=1$ , $f(x)$ is a convergent $p$ -series.

When $x=-1$ , $f(x)$ is a convergent alternating series.

So, the interval of convergence for $f(x)$ is the closed interval $\boxed{-1 \le x \le 1}$ .

The derivative of $f$ is the series

$\displaystyle f'(x) = \sum_{n=1}^\infty \frac{nx^{n-1}}{n^2} = \frac1x \sum_{n=1}^\infty \frac{x^n}n$

which also converges for $|x|$ by the ratio test:

$\displaystyle \lim_{n\to\infty} \left|\frac{x^{n+1}}{n+1} \cdot \frac n{x^n}\right| = |x| \lim_{n\to\infty} \frac{n}{n+1} = |x| < 1$

When $x=1$ , $f'(x)$ becomes the divergent harmonic series.

When $x=-1$ , $f'(x)$ is a convergent alternating series.

The interval of convergence for $f'(x)$ is then the closed-open interval $\boxed{-1 \le x < 1}$ .

Differentiating $f$ once more gives the series

$\displaystyle f''(x) = \sum_{n=1}^\infty \frac{n(n-1)x^{n-2}}{n^2} = \frac1{x^2} \sum_{n=1}^\infty \frac{(n-1)x^n}{n} = \frac1{x^2} \left(\sum_{n=1}^\infty x^n - \sum_{n=1}^\infty \frac{x^n}n\right)$

The first series is geometric and converges for $|x|$ , endpoints not included.

The second series is $f'(x)$ , which we know converges for $-1\le x$ .

Putting these intervals together, we see that $f''(x)$ converges only on the open interval $\boxed{-1 < x < 1}$ .

6 0

1 year ago

Find the value of 10x+3 if 10x=1,5​

Find the value of 10x+3 if 10x=1,5