Mg + O2 ➡️ MgO — we need to have the same emount of each element on both sides. On the left we have 1 Mg and on the right 1 Mg, so thats fine, but 2 O on the left and 1 O on the right, so we place a coefficient of 2 in front of the compound which is “lacking” O.
Mg + O2 ➡️ 2MgO
Now the O is okay, but we have 1 Mg and 2 Mg, so we need to put a 2 in front of the Mg thats “lacking”.
2M + O2 ➡️ 2MgO
Now it is balanced :)
Answer:
5.71 x 1021 (C)
Explanation:
Because if the numbers are over 5 then u round to the next number. So since 6 is bigger than 5 that means is gonna round up so it will be 7 and so. I hope that helps a bit
Answer:
(ANSWER)
2 KNO3 + H2CO3 = K2CO3 +2 HNO3 is the balanced equation.
PA BRAINLYES
Answer:
a. .250 moles
Explanation:
Hello!
In this case, since we can see how the hydrogen is given off as a product of the reaction and we can model its behavior via the ideal gas equation, it is possible for us to use such equation for the determination of the collected moles:
Next, since the STP conditions account for a pressure of 1 atm and a temperature of 273 K, the moles turn out to be:
Thus the answer is a. .250 moles
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Best regards!
calculate moles of both reagents given and the moles of FeS that each of them would form if they were in excess
moles = mass / molar mass
moles Fe = 7.62 g / 55.85 g/mol
= 0.1364 moles
1 mole Fe produces 1 mole FeS
Therefore 7.62 g Fe can form 0.1364 moles FeS
moles S = 8.67 g / 32.07 g/mol
= 0.2703 moles S
1 mole S can from 1 moles FeS
So 8.67 g S can produce 0.2703 moles FeS
The limiting reagent is the one that produces the least product. So Fe is limiting.
The maximum amount of FeS possible is from complete reaction of all the limiting reagent.
We have already determined that the Fe can form up to 0.1364 moles of FeS, so this is max amount of FeS you can get.
Convert to mass
hope this helps :)