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kvv77 [185]
3 years ago
8

At what pH are the moles of acid and base equal?

Chemistry
2 answers:
Elenna [48]3 years ago
8 0

Answer:

at 7

Explanation:

well i think the answer is at 7

mihalych1998 [28]3 years ago
5 0

Answer:

7

Explanation:

(Note: for a strong acid and strong base titration the equivalence point is at a pH=7. This is because at this point you have equal moles of added base as acid in the original solution. Therefore at the equivalence point the solution has formed a neutral salt and the pH is 7).

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Determine how many valence electrons magnesium contains
yanalaym [24]
There are two valence electrons.
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B, the height above or below sea level
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3 years ago
Solid aluminum metal reacts with aqueous zinc chloride to produce solid zinc metal and aqueous aluminum chloride
yuradex [85]

Answer:

2Al + 3ZnCl₂    →    3Zn + 2AlCl₃

Explanation:

Chemical equation:

Al + ZnCl₂    →    Zn + AlCl₃

Balanced Chemical equation:

2Al + 3ZnCl₂    →    3Zn + 2AlCl₃

This is the example of single displacement reaction. Al displace the zinc and form aluminium chloride and zinc metal.

There are two Al three zinc and six chlorine atoms on both side of equation so it is correctly balanced.

Thus it completely follow the law of conservation of mass.

Law of conservation of mass:

According to the law of conservation mass, mass can neither be created nor destroyed in a chemical equation.

This law was given by french chemist  Antoine Lavoisier in 1789. According to this law mass of reactant and mass of product must be equal, because masses are not created or destroyed in a chemical reaction.

7 0
3 years ago
Stannum has a body centered tetragonal with lattice constant, a = b = 5.83A and c = 3.18A. If the atomic radius is 0.145 nm, det
Fed [463]

Answer:

the atomic packing factor of Sn is 0.24

Explanation:

a = b = 5.83A and c = 3.18A.

Volume of unit cell = a²c

= (5.83)² *  3.18 * 10⁻²⁴ cm³

= 1.08 * 10⁻²²cm³

Volume of atoms =

2 \times  \frac{4}{3} \pi r^3

(∴ BCC, effective number of atom is 2)

Volume of atoms =

2 * \frac{4}{3} *3.14*(0.145*10^-^7cm)^3

= 2.55*10⁻²³cm³

\text {Atomic packing factor}=\frac{\text {volume occupied by atom}}{\text {volume of unit cell }}

=\frac{2.55*10^-^2^3}{1.08*10^-^2^2} \\\\=0.24

<h3>therefore, the atomic packing factor of Sn is 0.24</h3>
4 0
3 years ago
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