The three particles of any atom are
<u>electron</u>) the smallest particle and is held in shells around the nucleus of the atom
<u>proton</u>) is found in the nucleus and is much larger than an electron
<u>neutron</u>) the same mass as a proton and also found in the nucleus of the atom
Answer:
117.3 W is being removed.
Explanation:
The heat removed can be calculated as:
Q = m*c*ΔT
Where m is the mass, c is the specific heat and ΔT is the temperature variation. Because there're two components:
Q = mwater*cwater*ΔT + maluminum*caluminum*ΔT
Q = (mwater*cwater + maluminum*caluminum)*ΔT
Searching in a thermodynamic table:
cwater = 4.184 J/g°C
caluminium = 0.9 J/g°C
In 1 minute, the temperature decreases 2.2°C, so ΔT = -2.2°C
Q = (700*4.184 + 300*0.9) * (-2.2)
Q = -7037.36 J
The rate of energy is the potency (P), which is the heat divided by the time. So, for 1 minute (60 s):
P = -7037.36/60
P = -117.3 J/s
P = -117.3 W
The minus signal indicates that the energy is being removed.
<span>Option 4 is the correct answer. Rutherford concluded that the atom's volume was mostly empty space because the stream of alpha particles he directed at the gold foil arived at his detection aparatus mostly intact, indicating that relatively few of the alpha particles had been deflected. This follows because if the atom had not been empty space then the alpha particles would have encountered resistance and gone off course.</span>
Carbon can-be valence electron that could-be removed using the least amount of energy.
