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xxTIMURxx [149]
2 years ago
7

A research company surveys 8,000 people. The company expects 6,000 people to respond favorably. If there is a percent error of 2

.5%, what is the range of people who will respond favorably to the survey? please help
Mathematics
1 answer:
Aliun [14]2 years ago
8 0

Answer:

400

Step-by-step explanation:

6/8 = 0.75 or 75% expected to respond favorably.

Margin of error 2.5%:

  Lower bound: 0.75 - .025 = 0.725

  Upper bound: 0.75 + .025 = 0.775

Range:

  Lower bound: 8000 * 0.725 = 5800

  Upper bound: 8000 * 0.775 = 6200

  6200 - 5800 = 400

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I could not get it to work with all of those numbers. The only number that caused an issue was 29. I used 28 instead and it worked. I'm not sure if 29 was a typo, but I couldn't get 29 to work. 

3 0
3 years ago
Consider the following equation. 9x2 − y2 = 6 (a) Find y' by implicit differentiation. y' = (b) Solve the equation explicitly fo
qaws [65]

Answer:

Step-by-step explanation:

Given is an equation in x and y as

9x^2 - y^2 = 6

We use implicit method to differentiate the above equation

18x-2yy'=0

y' = 9x/y

b) to solve the equation explicitly for y and differentiate to get y' in terms of x. y' = ±

We separate the variables as

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Take square root

y=\sqrt{9x^2+2C} \\y=-\sqrt{9x^2+2C}

6 0
3 years ago
What is the value of this expression when a = 4, b= -5, and c= -7?<br> a + 2bc<br> 3a ?
sladkih [1.3K]

Answer:

1) -66

2)

Step-by-step explanation:

Given:

a=4

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c=-7

=a+2bc

=4+2*-5*7

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7 0
3 years ago
Read 2 more answers
Mr. O'Connor had $90 to spend at a football game. He spent 31/45 on his ticket. Then, he spent 3/7 of his remaining money at the
Kobotan [32]

He has $90 in total to spend

He spent (31/45) of this money on ticket

so money spent on ticket =(31/45) *90 =2790/45 =62

Now money left with him is 90-62 =28 $

Now it says that he spent (3/7) of this remaining money at concession stand

so money spent on concession stand =(3/7)*28 =84/7 =12

Now money left with him = 28-12 =16

So money left with him is $16 but hat costs for $18

So Mr. O'Connor didnt have enough moeny to buy the hat

4 0
3 years ago
Find the approximate solution(s) to each of the following equations graphically. Use technology to support your
ser-zykov [4K]

Answer: x" = 5.69

Step-by-step explanation:

The graphic solution is attached.

Verifying the solution:

Existence condition: x > 0

2x - 4 = √x + 5

√x =2x - 4 - 5

√x =2x - 9 (²)

x = (2x - 9)²

x = 4x² - 36x + 81

4x² - 36x - x + 81 = 0

4x² - 37x + 81 = 0

Δ = -37² - 4.4.81 = 1369 - 1296 = 73

x = 37 ±√73/8                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                          

x' = 3.55

x" = 5.69

checking:

2*3.55 - 4 = 3.1

√3.55 + 5 = 6.88 Its not the same ∴ 3.55 is not a solution

2*5.69 - 4 = 7.39

√5.69 + 5 = 7.39 ∴ it's the only solution

4 0
3 years ago
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