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storchak [24]
3 years ago
8

What is the percent yield for carbon dioxide if 10.0 grams of carbon

Chemistry
1 answer:
ivolga24 [154]3 years ago
3 0

The percent yield : 81.5%

<h3>Further explanation</h3>

Percent yield is the compare of the amount of product obtained from a reaction with the amount you calculated

General formula:

Percent yield = (Actual yield / theoretical yield )x 100%

An actual yield is the amount of product actually produced by the reaction. A theoretical yield is the amount of product that you calculate from the reaction equation according to the product and reactant coefficients

Reaction

2CO+O₂⇒2CO₂

mol CO(MW=28,01 g/mol)

\tt \dfrac{10}{28.01}=0.357

mass CO₂ (theoretical)(MW=44,01 g/mol)

\tt 0.357\times 44.01=15.712~g

the percent yield :

\tt \dfrac{12.81}{15.712}\times 100\%=81.5\%

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Answer the following questions for H2CrO4:
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How much 6.0 m hno3 is needed to neutralize 39ml of 2 m koh
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13mL

Explanation:

Step 1:

The balanced equation for the reaction. This is given below:

HNO3 + KOH —> KNO3 + H2O

From the balanced equation above, we obtained the following data:

Mole ratio of the acid (nA) = 1

Mole ratio of the base (nB) = 1

Step 2:

Data obtained from the question.

This includes the following:

Molarity of the acid (Ma) = 6M

Volume of the acid (Va) =?

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Molarity of the base (Mb) = 2M

Step 3:

Determination of the volume of the acid.

Using the equation:

MaVa/MbVb = nA/nB, the volume of the acid can be obtained as follow:

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