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Sliva [168]
3 years ago
15

Perform the following conversions. Show your work and give answer in scientific

Chemistry
1 answer:
MArishka [77]3 years ago
4 0

Answer:

3.398x10^{-10}km^2

Explanation:

Hello!

In this case, since this is a two-step conversion, we first need to compute the m² and then the km² as shown below:

3.398cm^2*(\frac{1m}{100cm} )^2=3.398cm^2*\frac{1m^2}{1x10^4cm^2} =3.398x10^{-4}m^2

Now from m² to km²:

3.398x10^{-4}m^2*(\frac{1km}{1000m} )^2=3.398x10^{-4}m^2*\frac{1km^2}{1x10^6m^2}=3.398x10^{-10}km^2

Best regards!

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What is the H+ concentration when pH is 2, 6, 7, 8, and 12?
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25. How many ml of a .0023M strontium hydroxide solution are needed to completely react 15.0 mL of 0.012M hydrochloric acid?
Mariana [72]

Answer: There are 78.26 mL of a 0.0023M strontium hydroxide solution are needed to completely react 15.0 mL of 0.012M hydrochloric acid.

Explanation:

Given: M_{1} = 0.0023 M,          V_{1} = ?

V_{2} = 15.0 mL,           M_{2} = 0.012 M

Formula used to calculate volume of strontium hydroxide solution is as follows.

M_{1}V_{1} = M_{2}V_{2}

Substitute the values into above formula as follows.

M_{1}V_{1} = M_{2}V_{2}\\0.0023 M \times V_{1} = 0.012 M \times 15.0 mL\\V_{1} = 78.26 mL

Thus, we can conclude that there are 78.26 mL of a 0.0023M strontium hydroxide solution are needed to completely react 15.0 mL of 0.012M hydrochloric acid.

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