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Sliva [168]
3 years ago
15

Perform the following conversions. Show your work and give answer in scientific

Chemistry
1 answer:
MArishka [77]3 years ago
4 0

Answer:

3.398x10^{-10}km^2

Explanation:

Hello!

In this case, since this is a two-step conversion, we first need to compute the m² and then the km² as shown below:

3.398cm^2*(\frac{1m}{100cm} )^2=3.398cm^2*\frac{1m^2}{1x10^4cm^2} =3.398x10^{-4}m^2

Now from m² to km²:

3.398x10^{-4}m^2*(\frac{1km}{1000m} )^2=3.398x10^{-4}m^2*\frac{1km^2}{1x10^6m^2}=3.398x10^{-10}km^2

Best regards!

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The volume of oxygen, collected over water, is 185 mL at 25 degrees Celsius and 600 torr. calculate the dry volume of the oxygen
ivolga24 [154]

Answer:

0.1593 L.

Explanation:

  • We can use the general law of ideal gas: PV = nRT.

where, P is the pressure of the gas in atm.

V is the volume of the gas in L.

n is the no. of moles of the gas in mol.

R is the general gas constant,

T is the temperature of the gas in K.

  • If n and P are constant, and have two different values of V and T:

<em>P₁V₁T₂ = P₂V₂T₁</em>

<em></em>

P₁ = 600 torr/760 = 0.789 atm, V₁ = 185.0 mL = 0.185 L, T₁ = 25.0°C + 273 = 298.0 K.

P₂ (at STP) = 1.0 atm, V₂ = ??? L, T₂ (at STP = 0.0°C) = 0.0°C + 273 = 273.0 K.

<em>∴ V₂ = P₁V₁T₂/P₂T₁</em> = (0.789 atm)(0.185 mL)(298.0 K)/(1.0 atm)(273.0 K) = <em>0.1593 L.</em>

4 0
4 years ago
What is the molarity of a solution if you take 12.0 grams of ca(no3)2 and mix it with 0.105 l of water?
Lunna [17]
The  molarity  of  a solution  if it tale 12.0   grams  of  Ca(No3)2  is  calculated as below

molarity =  moles/volume in liters
 moles = mass/molar mass =  12.0 g/ 164 g/mol =  0.073 moles

molarity is therefore  = 0.073/0.105 = 0.7 M 
8 0
3 years ago
The temperature of a 95.4 g piece of Cu increases from 25.0 °C to 48.0 °C when the Cu absorbs 849 J of heat. What is the specifc
melisa1 [442]
<h3>Answer:</h3>

0.387 J/g°C

<h3>Explanation:</h3>
  • To calculate the amount of heat absorbed or released by a substance we need to know its mass, change in temperature and its specific heat capacity.
  • Then to get quantity of heat absorbed or lost we multiply mass by specific heat capacity and change in temperature.
  • That is, Q = mcΔT

in our question we are given;

Mass of copper, m as 95.4 g

Initial temperature = 25 °C

Final temperature = 48 °C

Thus, change in temperature, ΔT = 23°C

Quantity of heat absorbed, Q as 849 J

We are required to calculate the specific heat capacity of copper

Rearranging the formula we get

c = Q ÷ mΔT

Therefore,

Specific heat capacity, c = 849 J ÷ (95.4 g × 23°C)

                                        = 0.3869 J/g°C

                                        = 0.387 J/g°C

Therefore, the specific heat capacity of copper is 0.387 J/g°C

3 0
3 years ago
A Carnot cycle operates between the temperatures limits of 400 K and 1600 K, and produces 3600 kW of net power. The rate of entr
TiliK225 [7]

The rate of entropy change:

The rate of entropy change of the working fluid during the heat addition process is 3 kW/K

What is the Carnot cycle?

  • The Carnot Cycle is a thermodynamic cycle made up of reversible isothermal expansion, adiabatic expansion, isothermal compression, and adiabatic compression processes in succession.
  • The ratio of the heat absorbed to the temperature at which the heat was absorbed determines the change in entropy.

The entropy of a system:

The rate of heat addition is expressed as,

Q = \frac{WT_{H}}{T_{H}- T_{L}}

The entropy of a system is a measure of how disorderly a system is getting. The rate of entropy generation during heat addition is,

S_{gen} = \frac{Q}{T_{H}} = \frac{W}{T_{H} - T_{L}}

Calculation:

<u>Given:</u>

T_{L} = 400K

T_{H} = 1600K

W = 3600 kW

Put all the values in the above equation, and we get,

S_{gen} = \frac{W}{T_{H} - T_{L}} = \frac{3600}{1600-400} = 3 kW/K

The rate of entropy change is 3 kW/K

Learn more about the Carnot cycle here,

brainly.com/question/13002075

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3 0
2 years ago
why might you find fossil evidence of both an ocean and a forest at different depths in the same location??
skad [1K]

Answer:

The fossil evidence of both an ocean and a forest can be found at different depths in the same location because there might have been a presence of both an ocean and a forest at the same location at different times in the history of Earth.

Explanation:

It is clear from various studies that the Earth has had a diverse geologic history in which events like drastic climate changes, upsurging of oceans, rapid desertification, etc., have taken place many times.

Thus, the possibility of an ocean and forest having shared a single location at different times in the history of Earth cannot be neglected.

7 0
2 years ago
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