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Degger [83]
3 years ago
12

Help me solve this problem please

Mathematics
1 answer:
lara31 [8.8K]3 years ago
5 0

Answer:

CD = 45

Step-by-step explanation:

CE = 180

( x + 6 ) + ( 4x - 21 ) = 180

5x - 15 = 180

5x = 195

x = 39

substitute x in CD

CD = x + 6

CD = 39 + 6

CD = 45

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Factor completely.
antiseptic1488 [7]

Answer:

B

Step-by-step explanation:

Given

y² - 12y + 32

Consider the factors of the constant term (+ 32) which sum to give the coefficient of the y- term (- 12)

The factors are - 4 and - 8, since

- 4 × - 8 = 32 and - 4 - 8 = - 12, thus

y² - 12y + 32 = (y - 4)(y - 8) → B

6 0
3 years ago
Read 2 more answers
Please help me on this will give you brainliest
enyata [817]

Answer:

135 x 10^7

Step-by-step explanation:

27(5 x 10^7)

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3 years ago
Which similarity statement expresses the relationship between the two triangles?
Dmitry_Shevchenko [17]

<em><u>Answer</u></em><em><u> </u></em><em><u>:</u></em><em><u>-</u></em><em><u> </u></em><em><u> </u></em><em><u>opti</u></em><em><u>on</u></em><em><u> </u></em><em><u>3</u></em><em><u>r</u></em><em><u>d</u></em><em><u> </u></em><em><u>!</u></em><em><u>!</u></em><em><u> </u></em>

Step-by-step explanation:

∆FGE ~ ∆ JKL

i.e, Angle FGE = angle JKL = 63°

and angle GEF = angle KLJ = 29°

also, angle GFE = angle KJL = 88°

so, the ∆FGE ~ ∆ JKL by AA property of similarity !!

• not other options because if we take corresponding angle they are not equal

For eg. for ∆ EFG ~ ∆ JKL

the angle EFG must be equal to angle JKL to be similar !!

but they are not equal !!

so, they are not similar !!

and such ,all other options except 3rd is wrong !!

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3 years ago
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Irina-Kira [14]
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Thus, the length of the base of the aquarium is \sqrt{area \ of \ base} = \sqrt{ \frac{20}{h} }

The frame is to cover 8 sides with the length equal to the length of the base and 4 sides with the length of the height.

Thus, the total perimeter of the frame is given by 8\sqrt{\frac{20}{h}}+4h= \sqrt{64\left(\frac{20}{h}\right)}+4h = \sqrt{\frac{1,280}{h}}+4h

Area of the four side faces of the aquarium is 4 times the length of the base times the height = 4\times\sqrt{ \frac{20}{h} }\times h=\sqrt{16\left(\frac{20}{h}\right)h^2}=\sqrt{320h}

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Therefore, total cost in terms of the height, h, is given by

C=\sqrt{\frac{62,720}{h}}+28h+\frac{160}{h}+\sqrt{20,480h
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nata0808 [166]

Answer:

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Step-by-step explanation:

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