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Degger [83]
3 years ago
12

Help me solve this problem please

Mathematics
1 answer:
lara31 [8.8K]3 years ago
5 0

Answer:

CD = 45

Step-by-step explanation:

CE = 180

( x + 6 ) + ( 4x - 21 ) = 180

5x - 15 = 180

5x = 195

x = 39

substitute x in CD

CD = x + 6

CD = 39 + 6

CD = 45

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Select the correct answer. Which triangles in the diagram are congruent? A. triangle 1 and triangle 2 B. triangle 1, triangle 2,
Juliette [100K]

Answer:

Triangle 1 and 3

Step-by-step explanation:

Based on a Congruent rule Side angle side :

In triangle 1 and triangle 3 are congruent by side angle side .

Therefore, the answer is triangle 1 and triangle 3.

5 0
3 years ago
Prove that 25^11−5^19 is divisible by 31.
SCORPION-xisa [38]

Answer:

Divisible by 3 is the answer

Step-by-step explanation:

First get everything to have the same base of 5

25^11 - 5^19

(5^2)^11 - 5^19

5^(2*11) - 5^19

5^22 - 5^19

Now factor out the GCF 5^19 to get

5^22 - 5^19

5^(19+3) - 5^(19+0)

5^19*5^3 - 5^19*5^0

5^19(5^3 - 5^0)

5^19(125 - 1)

5^19*(124)

At this point, we factor the 124 into 31*4 to end up with this full factorization: 5^19*31*4

Therefore, 25^11 - 5^19 is equivalent to 5^19*31*4

Since 31 is a factor of the original expression, this means the original expression is divisible by 31.

4 0
3 years ago
2+2?<br> please answer i need to graduate from highschool
tensa zangetsu [6.8K]

Hope this helps Answer:

4

6 0
2 years ago
Which way will the decimal go if you are dividing with decimals by a power of 10
astraxan [27]

Answer: Multiplying and Dividing Decimals by Powers of 10

When you divide a decimal by a power of 10, simply move the decimal place to the left as many places as there are 0s in the power of 10.

7 0
2 years ago
How many different 4 digit even numbers can be written using 0,5,6,3,8,7?<br><br> help asap please!!
fiasKO [112]

Step-by-step explanation:

I guess that means the digits can not be repeated in such a number.

let's start with how many numbers in general can be created :

we have 6 basic digits, and we are pulling 4 of them for a number.

if the sequence of the pulled digits would not matter, it would be combinations C (6, 4).

but we are creating different numbers, so the sequence of the digits does matter. so, it is permutations P (6, 4).

P(6, 4) = 6!/(6-4)! = 6!/2! = 6×5×4×3 = 360

so. bauxite, we can create 360 different 4 digit numbers out of these 6 digits.

but not all of them are wanted.

for example, I assume we don't want the numbers that start with a 0, because they would normally count as 3-digit numbers.

if that assumption is correct, we need to find how many would start with a 0, and subtract those from the total number.

since we are handling all 6 digits in the same way, an equal number must start with 0, with 5, with 6, with 3, with 8 and with 7.

so, 1/6 of the total number start with 0 : 360×1/6 = 60.

that means the total number of 4-digit numbers out of these 6 digits that do not start with 0 is 360-60 = 300.

but we are still not finished : we only want even numbers. that means they end with 0, 6 or 8.

in the same way we considered the first position, we consider also the last position. we have an equal amount of numbers that end with the different digits.

and so, we have 1/6 of 300 for each ending digit.

we want the specified 3 digits as end digits, so we get

3×1/6 of the 300 = 1/2 × 300 = 150

so, we can write 150 different 4-digit even numbers out of these 6 digits.

3 0
2 years ago
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