3 years ago

Find the surface area of the following cylinders. Round to the nearest hundredth.

Mathematics

1 answer:

Aleks [24]3 years ago

5 0

Answer:

surface area of cylinder= 2πrh + 2πr²

2×22/7×1×8+2×22/7×1×1

352. + 44

7. 7

= 50.3 + 6.25

= 56.55cm²

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Read 2 more answers

Complex numbers zj and zz are given by zj = 3- j2, zz = - 4 + j3. (a) express zj and zz in polar form. (b) find lz1l by first ap

inna [77]

Solution:

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Part a:

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zz = - 4 + j3 = $5e^{j143.1^{\circ}}$

Part b:

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z1z2 = $3.6e^{-j33.7^{\circ}}.5e^{j143.1^{\circ}}$

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