A test light with an electrical resistance of 9.00 S2 draws a current of 1.50 A when

Chemistry

1 answer:

yuradex [85]3 years ago

4 0

Answer:

20.25 W

Explanation:

Applying,

P = I²R.................... Equation 1

Where P = Power, I = current drawn by the test light, R = Resistance of the test light

From the question,

Given: I = 1.5 A, R = 9.00 Ω

Substitute these values into equation 1

P = (1.5²)(9)

P = 2.25×9

P = 20.25 W

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