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polet [3.4K]
3 years ago
10

A test light with an electrical resistance of 9.00 S2 draws a current of 1.50 A when

Chemistry
1 answer:
yuradex [85]3 years ago
4 0

Answer:

20.25 W

Explanation:

Applying,

P = I²R.................... Equation 1

Where P = Power, I = current drawn by the test light, R = Resistance of the test light

From the question,

Given: I = 1.5 A, R = 9.00 Ω

Substitute these values into equation 1

P = (1.5²)(9)

P = 2.25×9

P = 20.25 W

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Answer:

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Explanation:

a. When you are studying the kinetics of a reaction such as:

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General rate law must be like:

Rate = k×[A]ᵃ[B]ᵇ

You must make experiments change initial concentrations of A and B trying to find k, a and b parameters.

If you see experiments 1 and 3, concentration of A is doubled and the Rate of the reaction is doubled to. That means a = 1

Rate = k×[A]¹[B]ᵇ

In experiment 1 and to the concentration of B change from 1.50M to 2.50M but rate maintains the same. That is only possible if b = 0. (The kinetics of the reaction is indepent to [B]

Rate = k×[A][B]⁰

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b. Replacing with values of experiment 1 (You can do the same with experiment 3 obtaining the same) k is:

Rate = k×[A]

0.320M/s = k×[1.50M]

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3 years ago
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