Question

BY ANSWERING THIS QUESTION UR PUTTING IT ON UR MOM's LIFE THAT U WON'T STEAL MY POINTS.

Answer 1

Answer:

$T_2=-125.58\°C$

Explanation:

Hello!

In this case, considering the Gay-Lussac's law which describes the pressure-temperature behavior as a directly proportional relationship by holding the volume as constant, we write:

$\frac{T_1}{P_1} =\frac{T_2}{P_2}$

Whereas solving for the final temperature T2, we get:

$T_2=\frac{T_1P_2}{P_1}$

Thus, we plug in the given data (temperature in Kelvins) to obtain:

$T_2=\frac{(22+273.15)K*1.75atm}{3.50atm} \\\\T_2=147.58K-273.15\\\\T_2=-125.58\°C$

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