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Anestetic [448]
3 years ago
12

7) List three (3) automobile safety features currently used to minimize the risk of injury to its passengers. Relate these

Physics
1 answer:
r-ruslan [8.4K]3 years ago
3 0
Seatbelt- strapped in egg
air bag- cushion around the egg
brakes- parachute(bag that helps the egg go down slower)
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Earth is the only planet that has a _____ and a _____.
MArishka [77]
Oxygen and life is the only thing earth has

4 0
3 years ago
Help please help help help
poizon [28]
Mass (m) of the object is 1kg
Velocity (v) is 2m/s
and the height is 0
when the mechanical energy M.E is solved for m*v= 1(2)=2 so the M.E=2
3 0
3 years ago
A bicyclist rides 2.93 km due east, while the resistive force from the air has a magnitude of 8.65 N and points due west. The ri
Ilya [14]

Answer:

-50.6 kJ

Explanation:

The work done (W) on an object is given by:

W = (Fcosθ) * S

where F is the force, S is the displacement and θ is the angle between the force and displacement.

i) During the first trip riding east, S₁ = 2.93 km = 2930 m, F₁ = 8.65 N.

The displacement is due east and the force is due west, hence θ₁ = 180°. Therefore:

W₁ = (F₁ * cosθ₁)S₁ = (8,65 * cos(180))2930 = -25.3 kJ

ii) i) During the second trip riding west, S₂ = 2.93 km = 2930 m, F₂ = 8.65 N.

The displacement is due west and the force is due east, hence θ₂ = 180°. Therefore:

W₂ = (F₂ * cosθ₂)S₂ = (8,65 * cos(180))2930 = -25.3 kJ

work done by the resistive force during the round trip is:

W = W₁ + W₂ = -25.3 kJ + (-25.3 kJ) = -50.6 kJ

4 0
3 years ago
Assume you have a person with a mass of 65 kg riding a skateboard down a ramp. While they are
aliina [53]

Answer:

a) Eg = 3,060.72 j

b) Ek = 2,080 j

c) Etotal = 5,140.72 j

Explanation:

The given parameters are;

The mass of the person, m = 65 kg

The height of the person, h = 4.8 m

The speed of the person, v = 8.0 m/s

a) The gravitational potential energy, E_g = m·g·h

Where;

g = The acceleration due to gravity ≈ 9.81 m/s²

∴ Eg = 65 kg × 9.81 m/s² × 4.8 m = 3,060.72 j

Eg = 3,060.72 j

b) The kinetic energy, Ek = 1/2·m·v²

∴ Ek = 1/2 × 65 kg × (8.0 m/s)² = 2,080 j

Ek = 2,080 j

c) The constant total Mechanical Energy, Etotal = Eg + Ek

∴ Etotal = 3,060.72 j + 2,080 j = 5,140.72 j

Etotal = 5,140.72 j.

8 0
3 years ago
A constant force of 4.0 N acts on a variety of objects. The greatest acceleration will occur in the object that has
zaharov [31]
In the object that has, the least inertia.
8 0
3 years ago
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