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3 years ago

Discuss the role of the expanded functions dental assistant in making a provisional coverage

1 answer:

7 0

The expanded-function dental assistant (EFDA) can play a major role in the fabrication and temporary cementation of a provisional crown or bridge. It is the dentist’s and the EFDA’s responsibility to remain current with the new provisional materials and techniques that are available. It is essential that a provisional crown or bridge remain cemented while the fixed prosthesis is being prepared and delivered to the dental office. When the patient returns for final cementation of a fixed crown or bridge, the provisional should be cautiously removed without causing any fracture or harm, just in case it will need to be recemented if the final prostheses needs to be sent back to the lab for adjustments and remake.

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In an attempt to impress its friends, an acrobatic beetle runs and jumps off the bottom step of a flight of stairs. The step is

Aleks04 [339]

Answer:

0.3677181864 m

Explanation:

u = Velocity = 1.5 m/s

$\theta$ = Angle = 20°

y = -20 cm

Velocity components

$u_x=ucos\theta\\\Rightarrow u_x=1.5cos20\\\Rightarrow u_x=1.40953\ m/s$

$u_y=usin\theta\\\Rightarrow u_y=1.5sin20\\\Rightarrow u_y=0.51303\ m/s$

Acceleration components

$a_x=0$

$a_y=-9.81\ m/s^2$

$y=u_yt+\dfrac{1}{2}a_yt^2\\\Rightarrow -0.2=0.51303\times t+\dfrac{1}{2}\times -9.81t^2\\\Rightarrow 4.905t^2-0.51303t-0.2=0$

$t=\frac{-\left(-0.51303\right)+\sqrt{\left(-0.51303\right)^2-4\cdot \:4.905\left(-0.2\right)}}{2\cdot \:4.905}, \frac{-\left(-0.51303\right)-\sqrt{\left(-0.51303\right)^2-4\cdot \:4.905\left(-0.2\right)}}{2\cdot \:4.905}\\\Rightarrow t=0.26088, -0.15629$

Time taken is 0.26088 seconds

$x=u_xt+\dfrac{1}{2}a_xt^2\\\Rightarrow x=1.40953\times 0.26088\\\Rightarrow x=0.3677181864\ m$

The distance the beetle travels on the ground is 0.3677181864 m

6 0

3 years ago

Suppose that the coefficient of kinetic friction between Zak's feet and the floor, while wearing socks, is 0.250. Knowing this,

insens350 [35]

Answer:

The distance travel before stopping is 1.84 m

Explanation:

Given :

coefficient of kinetic friction $\mu_{k} = 0.250$

Zak's speed $v = 3 \frac{m}{s}$

Gravitational acceleration $g = 9.8$ $\frac{m}{s^{2} }$

Work done by frictional force is given by,

$W = \Delta K$

$\mu _{k} mg d = \frac{1}{2} m v^{2}$

$d = \frac{v^{2} }{2 g \mu _{k} }$

$d = \frac{9}{2 \times 9.8 \times 0.250}$

$d = 1.84$ m

Therefore, the distance travel before stopping is 1.84 m

3 0

3 years ago

The bleeder is opened at a caliper and no brake fluid flows out. Technician A says that this is normal and that brake fluid shou

horsena [70]

Answer: b) Technician B only

Explanation:

For the fact no break fluid flows out Of the bleeder valve when It’s opened, that means there’s a blockage stopping the fluid from flowing off.

5 0

3 years ago

Which of the following is not an example of a chemical reaction? Rust, Photosynthesis, Melting Ice, Heat from Fire?

FinnZ [79.3K]

Rust, photosynthesis, and heat from fire are all chemical reactions <span>because </span>new substances are formed and the chemical formula is changed. By doing this, bonds are broken and formed in the making of the new substance. Melting ice is physical change the molecules are still water molecules, it just changed physical form.

5 0

3 years ago

Read 2 more answers

A rescue plane wants to drop supplies to isolated mountain climbers on a rocky ridge 235 m below. If the plane is traveling hori

11111nata11111 [884]

Answer:

481 m

Explanation:

To fall 235 m, the time required is

t = √(2H/g)

t= √(2 $\times$ 235/9.8)

t=6.92 seconds.

The supplies will travel forward

6.92 $\times$ 69.4 ≈ 481 m

Therefore, the goods must be dropped 481 m in advance of the recipients.

5 0

3 years ago