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Flauer [41]
3 years ago
10

For which characteristic was this Chinese shar-pei MOST LIKELY selectively bred?

Chemistry
1 answer:
Mumz [18]3 years ago
8 0

Answer:

B

Explanation:

because every Chinese shar-pei has wrinkled skin.

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A West Virginia coal is burned at a rate of 8.02 kg/s. The coal has a sulfur content of 4.40 % and the bottom ash contains 2.80
aleksley [76]

Answer: The annual emission rate of SO2 is 1.08 × 10^{7} kg/yr

Explanation:

  • The rate <em>r</em> at which the coal is been burnt is 8.02 kg/s.
  • Amount of sulphur in the burning coal is given as 4.40 %

i.e., 4.4/100 × 8.02 = 0.353 kg/s. Which is equivalent to the rate at which the sulphur is been burnt.

  • Since the burning of sulphur oxidizes it to produce SO2, it follows that the non-oxidized portion of the sulphur will go with the bottom ash.

  • The bottom ash is said to contain 2.80 % of the input sulphur.

  • Hence the portion of the SO2 produced is 100 — 2.80 = 97.20 %.

  • The rate of the SO2 produced is percentage of SO2 × rate at high sulphur is been burnt.

  = 97.20/100 × 0.353 kg/s.

  = 0.343 kg/s.

  • To get the annual emission rate of SO2, we convert the kg/s into kg/yr.

1 kg/s = 1 kg/s × (60 × 60 × 24 × 365) s/yr

1 kg/s = 31536000 kg/yr

  • Therefore, 0.343 kg/s = 0.343 × 31536000 kg/yr

     = 10816848 kg/yr

     = 1.08 × 10^7 kg/yryr.

5 0
2 years ago
Can anyone help me with this?
satela [25.4K]

Answer:liquids and gases

Explanation:

friction

4 0
3 years ago
The compound magnesium iodide is a strong electrolyte write the reaction when solid magnesium iodide is put into water
mestny [16]
  The  reaction  for magnesium  iodide  when put into water  is  as below

 MgI2(s) →  Mg^2+(aq)   + 2I^-(aq)

when  magnesium iodide  but into water it dissociate/ ionize  completely  into  Mg^2+  and  2l^-   ions. Magnesium iodide dissociate/ionize  completely because  magnesium  iodide  is a strong electrolyte  which  dissociate/ ionize  completely into their ions  when it is put into   water .
7 0
3 years ago
Which of the following are true statements about equilibrium systems? For the following reaction at equilibrium: CaCO3(s) ⇌ CaO(
Grace [21]

Answer:

The first, third and fourth statements are correct.

Explanation:

1) For the following reaction at equilibrium: CaCO3(s) ⇌ CaO(s) + CO2(g) adding more CaCO3 will shift the equilibrium to the right.

⇒ Le Chatellier says As the CaCO3 concentration is increased, the system will attempt to undo that concentration change by shifting the balance to the right. <u>This statement is true.</u>

<u />

2) For the following reaction at equilibrium: CaCO3(s)⇌ CaO(s) + CO2(g) increasing the total pressure by adding Ar(g) will shift the equilibrium to the right.

⇒ Le chatellier says that if we increase the pressure, the equilibrium will shift to the side with the least number of particles.

Since the molar densities of CaO and CaCO3 are constant, they don't appear in the equilibrium expression. This is why only changes to the pressure (concentration) of CO2 affect the position of the equilibrium.

If the pressure in the container is increased by adding an inert or non-reacting gas, nothing happens to the amounts of CO2, CaO or CaCO3. The added gas won't affect the partial pressure of CO2. <u>This statement is false. </u>

3)For the following reaction at equilibrium: 2 H2(g) + O2(g) ⇌ 2 H2O(g) the equilibrium will shift to the left if the volume is doubled.

⇒ Le Chatellier says if we increase the pressure, the equilibrium will shift to the side with the most particles.

In this case we have 2 moles of H2 and 1 mole of O2 on the left side and 2 mole of H2O on the right side. This means on the left side are more particles. So the equilibrium will shift to the left, so <u>this statement is true.</u>

4) For the following reaction at equilibrium: H2(g) + F2(g) ⇌ 2HF(g) removing H2 will increase the amount of F2 present once equilibrium is reestablished. Increasing the temperature of an endothermic reaction shifts the equilibrium position to the right.

⇒ Le chatellier says if H2 will be removed (this means the left side will get less particles) so the equilibrium will shift to the left, to increase the amount of F2.

⇒Le chatelier says if we increase the temperature of an exotherm reaction , there will be less energy released. The equilibrium will shift to the side of the reactants (the left side).

If we increase the temperature of an endotherm reaction, the equilibrium will shift to the side of the products (the right side). <u>This statement is true.</u>

4 0
3 years ago
Two colleagues are measuring the melting point of a substance. They observe two ranges of melting point, at 134-137 °C and 132-1
marissa [1.9K]

Explanation:

impurities affect both melting point and boiling point

in the case of melting point it lowers the melting point

so I guess one of the samples Ie contained impurities

6 0
3 years ago
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