Answer: W = 2/L
Isolate the variable by dividing each side by factors that don't contain the variable.
Answer:
Substitute the 80°F where the F is in the equation. then just put the whole equation into your calculator. I got approximately 26.7.
The area of the shaded region is 40π/3 square cm if the radius of the small circle r is 3 cm and the radius of the large circle R is 7 cm.
<h3>What is a circle?</h3>
It is described as a set of points, where each point is at the same distance from a fixed point (called the center of a circle)
We have a circle in which the shaded region is shown.
The radius of the small circle r = 3 cm
The radius of the large circle R = 3+4 = 7 cm
The area of the shaded region:
= area of the large circle sector - an area of the small circle sector
= (120/360)[π7²] - (120/360)[π3²]
= 49π/3 - 3π
= 40π/3 square cm or
= 13.34π square cm
Thus, the area of the shaded region is 40π/3 square cm if the radius of the small circle r is 3 cm and the radius of the large circle R is 7 cm.
Learn more about circle here:
brainly.com/question/11833983
#SPJ1
Answer:
He has 3 quarters , 6 dimes and 16 nickles
Step-by-step explanation:
∵ Dimes is d , Quarter is q , nickels is n and pennies is p
∵ Quarter = 25 cents
∵ Dime = 10 cents
∵ Nickle = 5 cents
∵ Penny = 1 cent
∵ The remaining 35 coins are pennies ⇒ 35 cents
∵ He has $2.50 = 2.50 × 100 = 250 cents
∴ The value of quarters , dimes and nickels = 250 - 35 = 215 cents
∴ 25q + 10d + 5n = 215 ⇒ (1)
∵ d = 2q
∴ q = 1/2d ⇒ (2)
∵ n = 10 + d ⇒ (3)
Substitute (2) and (3) in (1)
∴ 25(1/2 d) + 10d + 5(10 + d) = 215
∴ 12.5d + 10d + 50 + 5d = 215
∴ 27.5d = 215 - 50
∴ 27.5d = 165
∴ d = 165 ÷ 27.5
∴ d = 6
∴ q = 1/2 (6) = 3
∴ n = 10 + 6 = 16
∴ He has 3 quarters , 6 dimes and 16 nickles
Answer:
t=21
Step-by-step explanation:
