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3 years ago

Which type of molecule is shown below?

Chemistry

2 answers:

denis-greek [22]3 years ago

3 0

The answer is A. It is an alkyn. There is a triple bond

Vadim26 [7]3 years ago

3 0

Alkene I think not sure

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Given the following equilibrium constants: Kb B(aq) + H2O(l) ⇌ HB+(aq) + OH−(aq) 1/Kw H+(aq) + OH−(aq) ⇌ H2O(l) What is the equi

bija089 [108]

Answer: The value of $K_c$ for the net reaction is $\frac{K_b}{K_w}$

Explanation:

The given chemical equations follows:

Equation 1: $B(aq.)+H_2O(l)\rightleftharpoons HB^+(aq.)+OH^-(aq.);K_b$

Equation 2: $H^+(aq.)+OH^-(aq.)\rightleftharpoons H_2O(l);\frac{1}{K_w}$

The net equation follows:

$B(aq.)+H^+(aq.)\rightleftharpoons HB^+(aq.);K_c$

As, the net reaction is the result of the addition of first equation and the second equation. So, the equilibrium constant for the net reaction will be the multiplication of first equilibrium constant and the second equilibrium constant.

The value of equilibrium constant for net reaction is:

$K_c=K_1\times K_2$

We are given:

$K_1=K_b$

$K_2=\frac{1}{K_w}$

Putting values in above equation, we get:

$K_c=K_b\times \frac{1}{K_w}=\frac{K_b}{K_w}$

Hence, the value of $K_c$ for the net reaction is $\frac{K_b}{K_w}$

7 0

3 years ago

Sodium phosphate and calcium chloride react to form sodium chloride and calcium phosphate. If you have 379.4 grams of calcium ch

barxatty [35]

Answer: 353.6 g.

Explanation:

1) Word equation (given)

Sodium phosphate + calcium choride → sodium chloride + calcium phosphate

2) Balanced chemical equation

2 Na₃PO₄ +3 CaCl₂ → 6 NaCl + Ca₃(PO4)₂

3) Mole ratio

2 moles Na₃PO₄ : 3 moles CaCl₂ : 6 moles NaCl : 1 mole Ca₃(PO4)₂

4) Formula to convert grams to moles

number of moles = mass in grams / molar mass

5) Number of moles of limiting reactant

a) mass in grams = 379.4 g CaCl₂

b) molar mass CaCl₂ = 110.98 g/mol

c) number of moles CaCl₂ = 379.4 g / 110.98 g/mol = 3.419 moles

6) Theoretical yield of Ca₃(PO4)₂

3 moles CaCl₂ / 1 mole Ca₃(PO4)₂ = 3.419 moles CaCl₂ / x ⇒

x = 3.419 × 1 / 3 = 1.140 moles Ca₃(PO4)₂

7) Convert 1.140 moles Ca₃(PO4)₂

a) molar mass Ca₃(PO4)₂ = 310.1767 g/mol

b) mass in grams = number of moles × molar mass = 1.140 moles × 310.1767 g/mol = 353.6 g ← answer.

7 0

3 years ago

Fill in the flowing information for the element uranium

UkoKoshka [18]

Answer:

Period: 7

Family: actinides

Group: Actinide

Explanation:

6 0

3 years ago

Read 2 more answers

B. If the sand you ran across has a specific-heat capacity of 835 J/(kgºc),

Murrr4er [49]

Answer: 16700 Joules

Explanation:

The quantity of heat required to raise the temperature of a substance by one degree Celsius is called the specific heat capacity.

$Q=m\times c\times \Delta T$

Q = Heat absorbed = ?

m = mass of sand = 2 kg

c = heat capacity = $835J/kg^0C$

Initial temperature = $T_i$ = $40^0C$

Final temperature= $T_f$ = $50^0C$

Change in temperature , $\Delta T=T_f-T_i=(50-40)^0C=10^0C$

Putting in the values, we get:

$Q=2kg\times 835J/kg^0C\times 10^0C$

$Q=16700J$

16700 J of energy must be added to a 2-kilogram pile of it to increase its temperature from 40°C to 50°C

4 0

2 years ago

Lonization energy is the

Tamiku [17]

Arrow on the table below draw an

3 0

2 years ago