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ludmilkaskok [199]
3 years ago
14

If 1000g of water from Luboc River contains 0.0075g of Ca2+ ion, what is the concentration in ppm by mass of Ca2+ present in Lub

oc River?
Chemistry
1 answer:
marin [14]3 years ago
5 0

7.5 ppm

<h3>Further explanation</h3>

Given

1000 g of water

0.0075g of Ca²⁺ ion

Required

the concentration in ppm by mass of Ca²⁺

Solution

ppm = part per million

solvent = water ⇒ ppm = 1 mg/L(water density is 1 kg / L) or mg/kg

Convert g to mg of  Ca²⁺ ion :

0.0075 g = 7.5 x 10⁻³ g = 7.5 mg

Convert g to kg of water :

1000 g = 1 kg water

So the concentration of Ca²⁺ ion :

= 7.5 mg / 1 kg

= 7.5 ppm

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Need help !!!!! ASAP
Nat2105 [25]
<h2>Hello!</h2>

The answer is:

The temperature will be the same, 37°C.

<h2>Why?</h2>

Since from the statemet we know the first temperature, pressure and volumen of a gas, and we need to calculate the new temperature after the pressure and the volume changed, we need to use the Combined Gas Law.

The Combined Gas Law establishes a relationship between the temperature, the pressure and the volume of an ideal gas using Boyle's Law, Gay-Lussac's Law and Charles's Law.

The law establishes the following equation:

\frac{P_{1}V{1}}{T_{1}}=\frac{P_{2}V{2}}{T_{2}}

Where,

P_{1} is the first pressure.

V_{1} is the first volume.

T_{1} is the first temperature.

P_{2} is the second pressure.

V_{2} is the second volume.

T_{2} is the second temperature.

Then, we are given the following information:

V_{1}=200mL\\P_{1}=4atm\\T_{1}=37\°C\\V_{2}=400mL\\P_{2}=2atm

So, isolating the new temperature and substituting the given information, we have:

\frac{P_{1}V{1}}{T_{1}}=\frac{P_{2}V{2}}{T_{2}}\\\\T_{2}=P_{2}V{2}*\frac{T_{1}}{P_{1}V_{1}} \\\\T_{2}=2atm*400mL*\frac{37\°C}{4atm*200mL}=37\°C

Hence, we have that the temperature will not change because both pressure and volume decreased and increased proportionally, creating the same relationship that we had before the experiment started.

The temperature will be the same, 37°C

Have a nice day!

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Furthermore, the number of electrons in a neutral atom equals number of protons. Hence, there are 11 protons in this element.

Also, number of protons equal atomic number therefore, the atomic number of this element is 11. And, by checking periodic table, the element having atomic number 11 is Sodium (Na).

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