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stich3 [128]
3 years ago
13

Air, Sea water, alloy afe the examples of

Chemistry
1 answer:
ratelena [41]3 years ago
8 0

Answer:

B. Mixture

because air,sea water and alloy are example of Mixture

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In order to become ________, ions will combine with other ions to form new substances.
horrorfan [7]
The answer is "More Stable."
7 0
3 years ago
When sulfuric acid and potassium hydroxide neutralize each other to make water and potassium sulfate, how is water formed?
statuscvo [17]
It's formed by the hydrogen ion of the acid and the hydroxide of the base. 

H_{2} SO_{4} + 2KOH --\ \textgreater \  K_{2} SO_{4} + 2H_{2}O
Sulfuric Acid + potassium superoxide --> Potassium Sulfate + Heavy Water

Hope this Helps :)
3 0
4 years ago
The following sequence of reactions occurs in the commercial production of aqueous nitric acid: 4NH3(g)+5O2(g)⟶4NO(g)+6H2O(l)ΔH=
castortr0y [4]

Answer:

The total energy change for the production of one mole of aqueous nitric acid is −494 kJ

Explanation:

<u>Step 1</u>: Data given

4NH3(g)+5O2(g)⟶4NO(g)+6H2O(l)ΔH=−907kJ 2NO(g)+O2(g)⟶2NO2(g)ΔH=−113kJ 3NO2+H2O(l)⟶2HNO3(aq)+NO(g)ΔH=−139kJ

<u>Step 2:</u> Multiply equations

Multiply the first equation by 3:

12 NH3(g) + 15 O2(g) → 12 NO(g) + 18 H2O(l) ΔH = −2721 kJ

Multiply the second equation by 6:

12 NO(g) + 6 O2(g) → 12 NO2(g) ΔH = −678 kJ

Multiply the third equation by 4:

12 NO2(g) + 4 H2O(l) → 8 HNO3(aq) + 4 NO(g) ΔH = −556 kJ

<u>Step 3:</u> Get the equations together

12 NH3(g) + 15 O2(g) + 12 NO(g) + 6 O2(g) + 12 NO2(g) + 4 H2O(l) →

12 NO(g) + 18 H2O(l) + 12 NO2(g) + 8 HNO3(aq) + 4 NO(g)

ΔH = −2721 kJ − 678 kJ − 556 kJ

We can simplify as followed:

12 NH3(g) + 21 O2(g) → 14 H2O(l) + 8 HNO3(aq) + 4 NO(g) ΔH = −3955 kJ

<u> Step 4:</u> Determine the total energy change for the production of one mole of aqueous nitric acid by this process:

−3955 kJ/8 moles HNO3= −494 kJ

The total energy change for the production of one mole of aqueous nitric acid is −494 kJ

3 0
3 years ago
What is the law of conservation and what happens when two substances at different temperatures come into contact.
insens350 [35]

Answer:

- Both energy and matter cannot be neither created nor destroyed.

- An equilibrium temperature will be reached.

Explanation:

Hello,

In this case, the law of conservation is applied to both matter and energy, and it states that both energy and matter cannot be neither created nor destroyed. Specifically, in chemical reactions, it states that in closed systems, the mass of the reactants equals the mass of the products even when the number of moles change. Moreover, for energy, if two substances at different temperatures come into contact, the hot one will cool down and the cold one will heat up until an equilibrium temperature so the energy lost by the hot one is gained by the cold one, which accounts for the transformation of energy.

Best regards.

4 0
3 years ago
How many sodium atoms are present in 0.2310 g of sodium?
umka21 [38]

The number of atoms present in 0.231 g of sodium is 6.02 x 10²¹ atoms.

The given parameters;

  • <em>mass of the reacting sodium = 0.231 g</em>
  • <em>1 mole of an atom = 6.02 x 10²³ atoms</em>
  • <em>the atomic mass of sodium is 23 g/mol</em>

The number of moles of 0.231 g of sodium available is calculated as;

no. \ of \ moles = \frac{Reacting \ mass}{Molar \ mass} \\\\no. \ of \ moles = \frac{0.231}{23} \\\\no. \ of \ moles = 0.01 \ mol.

The number of atoms of 0.01 mole of sodium available is calculated as;

1 mole ---------- 6.02 x 10²³ atoms

0.01 ----------------- ?

= 0.01 x 6.02 x 10²³ atoms

= 6.02 x 10²¹ atoms.

Thus, the number of atoms present in 0.231 g of sodium is 6.02 x 10²¹ atoms.

Learn more here:brainly.com/question/11461637

7 0
3 years ago
Read 2 more answers
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