<u>Answer:</u> The partial pressure of oxygen is 160 mmHg
<u>Explanation:</u>
We are given:
Percent of oxygen in air = 21 %
Mole fraction of oxygen in air = 
To calculate the partial pressure of oxygen, we use the equation given by Raoult's law, which is:

where,
= partial pressure of oxygen = ?
= total pressure of air = 760 mmHg
= mole fraction of oxygen = 0.21
Putting values in above equation, we get:

Hence, the partial pressure of oxygen is 160 mmHg
The volume of chlorine required is 7.71 L.
The reaction between phosphorus and chlorine is:
2P + 5Cl₂→ 5PCl₅
Therefore, 2 moles of P requires 5 moles of chlorine to react with it.
Given mass of P =3.39 g
Molar mass of P=30.97 g/mol
No. of moles of P = given mass/ molar mass = 3.39 / 30.97 = 0.109 moles
2 moles of P requires 5 moles of chlorine
0.109 moles of P will require 0.109 x 5/2 = 0.2725 moles of chlorine
According to ideal gas equation
PV=nRT
2.04 x V = 0.2725 x 0.0821 x 703
V = 0.2725 x 0.0821 x 703 / 2.04
V = 7.71L
Learn more about ideal gas equation here:
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Explanation:
To determine the charge on a given transition metal atom, you have to consider what element it is, the charges on the other atoms in the molecule, and the net charge on the molecule itself. The charges are always whole numbers, and the sum of all the atomic charges equals the charge on the molecule
B) chemical bond i believe is the correct answer
It’s definitely magnesium but it may not be