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IRINA_888 [86]
3 years ago
10

What determines when a system reaches equilibrium? What observations can be made about a system once equilibrium has been establ

ished?
Chemistry
1 answer:
Irina-Kira [14]3 years ago
5 0
Equilibrium is achieved when the reaction rate of the forward and backward reaction are equal or the concentrations of the reactants and the products are in an unchanging ratio. Specifically, this system is in a dynamic equilibrium.
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. Calculate the final Celsius temperature of sulfur dioxide gas if 50.0 mL of the gas at 20 C and 0.450 atm is heated until the
Anna [14]

Answer:

The final temperature of sulfur dioxide gas is 215.43 C

Explanation:

Gay Lussac's Law establishes the relationship between the temperature and the pressure of a gas when the volume is constant. This law says that if the temperature increases the pressure increases, while if the temperature decreases the pressure decreases. In other words, the pressure and temperature are directly proportional quantities.

Mathematically, the Gay-Lussac law states that, when a gas undergoes a transformation at constant volume, the quotient of the pressure exerted by the temperature of the gas remains constant:

\frac{P}{T}=k

Assuming you have a gas that is at a pressure P1 and at a temperature T1 at the beginning of the experiment, by varying the temperature to a new value T2, then the pressure will change to P2, and it will be true:

\frac{P1}{T1} =\frac{P2}{T2}

The reference temperature is the absolute temperature (in degrees Kelvin)

In this case:

  • P1= 0.450 atm
  • T1= 20 C= 293.15 K (being 0 C= 273.15 K)
  • P2=0.750 atm
  • T2= ?

Replacing:

\frac{0.450atm}{293.15 K} =\frac{0.750 atm}{T2}

Solving:

T2 =\frac{0.750 atm}{\frac{0.450atm}{293.15 K} }

T2=\frac{0.750 atm}{0.450 atm} *293.15K

T2=488.58 K

Being 273.15 K= 0 C, then 488.58 K= 215.43 C

<u><em>The final temperature of sulfur dioxide gas is 215.43 C</em></u>

6 0
3 years ago
The enthalpy change for converting 10.0 g of ice at -25.0 °C to water at 90.0 °C is __________ kJ. The specific heats of ice, wa
Nina [5.8K]
AH1 = m * c1 * AT1 calculate this for ice (-25C to 0C) AH2 = AHfus(1 mole)=6.01 kJ = 6010 J AH3 = m *c3 * AT3 calculat this for water (0C to 100C) AH4 = AHvap(1mole)=40.67 kJ = 40670 J AH5= m * c5 * AT5 calculate this for steam (100C to 125C) 
Sum ---- AH1+AH2+AH3+AH4+AH5 
Data m=18g (1mole water) 
c1=specific heat ice= 2.09 J/g K c3=specific heat water= 4.18 J/g K c5=specific heat steam= 1.84 J/g K 
AT = (Tend - Tinitial) as this is a difference between temperatures it doesn't matter the units Celsius or Kelvin. Kelvin (K)=Celsius (C)+273.15 
AT1 = 0C - (-25C)= 25C= 273.15K - 248.15K= 25K AT3= 100C - 0C = 100C= 100K AT5= 125C - 100C= 25C=25K
6 0
3 years ago
If you had a beaker full of black powder which of the following could you have?
Evgesh-ka [11]
A beaker of black powder can be a mixture with different substances (i.e gunpowder: a mixture of sulfur, charcoal, etc.), an element which can probably be carbon (known as black), and a compound as well which can be potassium nitrate. Hence, the answer is D. 
8 0
3 years ago
Read 2 more answers
There are several differences between chemical and physical changes. Which process is a sign of a chemical change? A. Rotting po
Nataly [62]

Answer:

A. a rotten potato gives all of bad smell

Explanation:

B,C,D are all physical changes because we can reverse them back.we can cool the water back to make ice. if the wind passes again we can randomly get the same cloud shape in c. and in d we can make that statue again. but in A can we reverse the rotting process ? ( the enzyme reaction) no we cant because it is a chemical reaction it gives a bad smell because of the chemical changes occuring in it.

hope this helps

8 0
2 years ago
What is the role of a catalyst in a chemical reaction?
Zinaida [17]

A catalyst is a substance that increases the rate of a chemical reaction by lowering the activation energy without itself being consumed by the reaction.

4 0
2 years ago
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